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anonymous
 4 years ago
\[(2^{1}x ^{2}y ^{1})^{2}(2x ^{3}y)^{2}(16x ^{3}y ^{3})^{0}/ (2x ^{3}y ^{5)^{2}}\]
anonymous
 4 years ago
\[(2^{1}x ^{2}y ^{1})^{2}(2x ^{3}y)^{2}(16x ^{3}y ^{3})^{0}/ (2x ^{3}y ^{5)^{2}}\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x^{13} y^{25}}{2} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Rottobey can you show me how you got that answer. since the answer is x^18 y^6/4. I'm just little lost on the equation (16x ^{3}y ^{3})^{0) is the zero represent all the number inside the equation is zero or one itself

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's fine Robtobey, I thank you for your help. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is a syntax error in the last term. The following is a step by step evaluation of the problem expression.\[\left(\left(\frac{1}{2} \frac{1}{x^2} \frac{1}{y}\right){}^{\wedge}(2)\right) \left(\left(\frac{2}{x^3} y\right){}^{\wedge}(2) \right)\left(\left(\frac{16}{x^3} y^3\right){}^{\wedge}(0)\right)/\left(\frac{2}{x^3} \frac{1}{y^5}\right){}^{\wedge}(2) \]\[\frac{\left(4 x^4 y^2\right)\left(\frac{x^6}{4 y^2}\right) (1)}{\left(\frac{4}{x^6 y^{10}}\right)} \]\[\frac{x^{10}}{\frac{4}{x^6 y^{10}}} \]\[\frac{x^{16} y^{10}}{4} \]WolframAlpha.com agrees http://www.wolframalpha.com/input/?i=simplify+((1%2F2+1%2Fx%5E2+1%2Fy)%5E(2))+((2%2Fx%5E3+y)%5E(2))+((16%2Fx%5E3+y%5E3)%5E(0))%2F(2%2Fx%5E3+1%2Fy%5E5)%5E(2)&t=sftb01

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The divisor should have been written as an equivalent to the following: ( (2 x^3)(y^5) )^2
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