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anonymous
 5 years ago
(2x ^{3} yz ^{6}) (2x)^{5} (I'm little lost on how to get y/16^8 z^6) ?.? only at this part (32x^5)/2x^3yz^6
anonymous
 5 years ago
(2x ^{3} yz ^{6}) (2x)^{5} (I'm little lost on how to get y/16^8 z^6) ?.? only at this part (32x^5)/2x^3yz^6

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327351420225:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2^{1}x ^{2}y ^{1})^{2}(2x ^{3}y)^{2}(16x ^{3}y ^{3})^{0}/ (2x ^{3}y ^{5)^{2}}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first multiply each exponent in the first large parentheses times the 2. Then in the second large parentheses the zero exponent will make the whole term equal to 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that should get you started.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I starting to understand a little, now I'm little confuse on this part (4x^4y^2) (2x^6 y ^2) (xy)/ 4x^6 y^10. ?.?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327353996471:dw I am not sure that I have all of your parentheses correctly written out...take a look and see...
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