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i cant make head nor hair of it

So I guess we should replace x with y-1

write*

that is how i see it anyways

you could look at the Taylor polynomial

doesnt (y-1)^3 expand with a y^2 in it?

y^3, 3y^2, 3y, 1

expanding all those terms would create y^2 s

oh yeah you are right

that wouldn't be efficient lol

so we should look at zarkon's way

well, if its the y^2 coeffs; its the pascal triangle diag then

2,1,0
^
1
3
6
...

assuming myins interp is good :)

..... the L of the pascal .... thats equal to the next ones entry ....

|dw:1327354588092:dw|

you want a polly that looks like this
\[\sum_{k=0}^{17}a_ky^k\]
there \(y=x+1\)

*where y=x+1

1
1* 1
1 2* 1
1 3 3* 1
1 4 6 4* 1
1510 (10) 5 1

but i think my idea has + and - signs to deal with still

I get 816 as the answer

\[{{18}\choose {3}}=816.too\]

using the Taylor polly amounts to computing
\[\frac{\displaystyle\sum_{k=1}^{17}k(k-1)}{2}\]