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anonymous
 5 years ago
The polynomial 1x+x ^{2}x ^{3}+...x ^{15}+x ^{16}x ^{17} can be written as a polynomial in y=x+1. Find the coefficient of y ^{2}
anonymous
 5 years ago
The polynomial 1x+x ^{2}x ^{3}+...x ^{15}+x ^{16}x ^{17} can be written as a polynomial in y=x+1. Find the coefficient of y ^{2}

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i cant make head nor hair of it

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0So I guess we should replace x with y1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[1(y1)+(y1)^2(y1)^3+(y1)^4 \cdots \] we really don't need to right this any further all of them will be larger degree than y^2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0that is how i see it anyways

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.0you could look at the Taylor polynomial

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0doesnt (y1)^3 expand with a y^2 in it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0expanding all those terms would create y^2 s

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0oh yeah you are right

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0that wouldn't be efficient lol

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we should look at zarkon's way

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well, if its the y^2 coeffs; its the pascal triangle diag then

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0assuming myins interp is good :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0..... the L of the pascal .... thats equal to the next ones entry ....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327354588092:dw

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.0you want a polly that looks like this \[\sum_{k=0}^{17}a_ky^k\] there \(y=x+1\)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01 1* 1 1 2* 1 1 3 3* 1 1 4 6 4* 1 1510 (10) 5 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but i think my idea has + and  signs to deal with still

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[{{18}\choose {3}}=816.too\]

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1I notice that the person you guys are trying to assist has not said a word yet. @kwenisha  does all this make any sense to you? have you attempted it yourself using a different method? any thoughts?

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.0using the Taylor polly amounts to computing \[\frac{\displaystyle\sum_{k=1}^{17}k(k1)}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@Asnaseer, I am actually trying understand it while working with my partner... I apologize if I come off as just trying to get the answer and not trying to understand it...

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1thats fine @kwenisha  I was just worried in case the experts above left you dazed. :)
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