anonymous
  • anonymous
when do i use sin, cos and tan in inverse form?
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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asnaseer
  • asnaseer
an example might be that you are told the sin of an angle is 0.5 and asked to find the angle. then you would use the inverse sin function.
asnaseer
  • asnaseer
does that help?
anonymous
  • anonymous
so when looking for the sides of a triangle?

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asnaseer
  • asnaseer
when looking for sides, you usually use the sin/cos/tan functions. the inverses are usually used to find the angles.
asnaseer
  • asnaseer
so you might be given an angle and one side, and asked to find another side - that involves using sin/cos/tan. on the other hand, you might be given 2 sides and asked to find the angle - that involves using the inverse functions.
anonymous
  • anonymous
ohh ok... |dw:1327355865365:dw| how would i do this?
asnaseer
  • asnaseer
\[\cos(60)=\frac{5}{x}\]therefore:\[x=\frac{5}{\cos(60)}\]
anonymous
  • anonymous
cosine is a/h?
asnaseer
  • asnaseer
yes
asnaseer
  • asnaseer
you can use the mneumonic SohCahToa to remember them. Soh ===> sin = o/h Cah ===> cos = a/h Toa ===> tan = o/a
asnaseer
  • asnaseer
you pronounce it as "SAW CAH TOE AH"
anonymous
  • anonymous
when i have that e
anonymous
  • anonymous
equation set up.. how do you solve for the x tho?
asnaseer
  • asnaseer
just work out the fraction - 5 divided by cosine of 60 degrees. I'm not sure where you are stuck?
anonymous
  • anonymous
sry.. i thought it was 5/x tho?
asnaseer
  • asnaseer
ok - let me try to explain it step by step...
anonymous
  • anonymous
thank you im horrible at math
asnaseer
  • asnaseer
ok, we know:\[\cos(60)=\frac{5}{x}\]are you happy with this statement?
anonymous
  • anonymous
yes
asnaseer
  • asnaseer
good. so 1st step is to get rid of the 'x' in the fraction on the right hand side. the way you do that is to multiply both sides by 'x' as follows:\[x*\cos(60)=x*\frac{5}{x}\]
asnaseer
  • asnaseer
now, on the right hand side, the 'x' at the top and bottom of the fraction will cancel out to give you:\[x*\cos(60)=\cancel{x}*\frac{5}{\cancel{x}}=5\]
asnaseer
  • asnaseer
follow it so far?
anonymous
  • anonymous
yes!
asnaseer
  • asnaseer
ok, so next step we want to do is to leave just 'x' on the left hand side. that can be done by dividing both sides by \(\cos(60)\) as follows:\[\frac{x*\cos(60)}{\cos(6)}=\frac{5}{\cos(60)}\]
asnaseer
  • asnaseer
then you'll notice the \(\cos(60)\)'s on the left hand side cancel each other out to give you:\[\frac{x*\cancel{\cos(60)}}{\cancel{\cos(6)}}=\frac{5}{\cos(60)}\]\[x=\frac{5}{\cos(60)}\]
asnaseer
  • asnaseer
make sense?
anonymous
  • anonymous
yea.. for that would you get...-5.24?
asnaseer
  • asnaseer
\[\cos(60)=0.5\]so:\[x=\frac{5}{\cos(60)}=\frac{5}{0.5}=10\]
asnaseer
  • asnaseer
maybe you entered 60 as radians instead of degrees in your calculator?
anonymous
  • anonymous
yup :)
asnaseer
  • asnaseer
don't worry - we've all been there :)
anonymous
  • anonymous
do u know how to find all sic trig functions...? lol
asnaseer
  • asnaseer
sic?
anonymous
  • anonymous
six*
asnaseer
  • asnaseer
You might find this site useful: http://www.ping.be/~ping1339/gonio.htm
anonymous
  • anonymous
okay
asnaseer
  • asnaseer
best thing to do is to keep practicing and post a question in this group when you get stuck on a particular problem. there are MANY people here who will be more than willing to spend time explaining things to you.
anonymous
  • anonymous
okay thank you for helping
asnaseer
  • asnaseer
yw

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