when do i use sin, cos and tan in inverse form?

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when do i use sin, cos and tan in inverse form?

Mathematics
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an example might be that you are told the sin of an angle is 0.5 and asked to find the angle. then you would use the inverse sin function.
does that help?
so when looking for the sides of a triangle?

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when looking for sides, you usually use the sin/cos/tan functions. the inverses are usually used to find the angles.
so you might be given an angle and one side, and asked to find another side - that involves using sin/cos/tan. on the other hand, you might be given 2 sides and asked to find the angle - that involves using the inverse functions.
ohh ok... |dw:1327355865365:dw| how would i do this?
\[\cos(60)=\frac{5}{x}\]therefore:\[x=\frac{5}{\cos(60)}\]
cosine is a/h?
yes
you can use the mneumonic SohCahToa to remember them. Soh ===> sin = o/h Cah ===> cos = a/h Toa ===> tan = o/a
you pronounce it as "SAW CAH TOE AH"
when i have that e
equation set up.. how do you solve for the x tho?
just work out the fraction - 5 divided by cosine of 60 degrees. I'm not sure where you are stuck?
sry.. i thought it was 5/x tho?
ok - let me try to explain it step by step...
thank you im horrible at math
ok, we know:\[\cos(60)=\frac{5}{x}\]are you happy with this statement?
yes
good. so 1st step is to get rid of the 'x' in the fraction on the right hand side. the way you do that is to multiply both sides by 'x' as follows:\[x*\cos(60)=x*\frac{5}{x}\]
now, on the right hand side, the 'x' at the top and bottom of the fraction will cancel out to give you:\[x*\cos(60)=\cancel{x}*\frac{5}{\cancel{x}}=5\]
follow it so far?
yes!
ok, so next step we want to do is to leave just 'x' on the left hand side. that can be done by dividing both sides by \(\cos(60)\) as follows:\[\frac{x*\cos(60)}{\cos(6)}=\frac{5}{\cos(60)}\]
then you'll notice the \(\cos(60)\)'s on the left hand side cancel each other out to give you:\[\frac{x*\cancel{\cos(60)}}{\cancel{\cos(6)}}=\frac{5}{\cos(60)}\]\[x=\frac{5}{\cos(60)}\]
make sense?
yea.. for that would you get...-5.24?
\[\cos(60)=0.5\]so:\[x=\frac{5}{\cos(60)}=\frac{5}{0.5}=10\]
maybe you entered 60 as radians instead of degrees in your calculator?
yup :)
don't worry - we've all been there :)
do u know how to find all sic trig functions...? lol
sic?
six*
You might find this site useful: http://www.ping.be/~ping1339/gonio.htm
okay
best thing to do is to keep practicing and post a question in this group when you get stuck on a particular problem. there are MANY people here who will be more than willing to spend time explaining things to you.
okay thank you for helping
yw

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