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subtract one vector from the other to get it to the origin; is my first thought
but my first thought aint always too good :)
maybe better idea. magnitude of b * height; where height is the "a"sin(a)
the determinate of the vector matrix of the first one would be good, but not work out to well for the second
i can recall the dot product stuff for cos(t) but never for sin(t) for some reason
The cross product a × b is defined as a vector c that is perpendicular to both a and b, with a direction given by the right-hand rule and a magnitude equal to the area of the parallelogram that the vectors span. from the wiki i think
so |axb| seems to be the area of the parallelogram if im reading this right
now i gotta recall how to cross a 2component vector
3 components i can do :)
ii) a= (4 -5 3) and b= (7 2 -4) --------------- x = 20-6 = 14 y=-(-16-21) = 37 z = 8+35 = 43 sqre them add them and sqrt them for magnitude; might wanna use a calcultor :)
http://www.wolframalpha.com/input/?i=sqrt%2814%5E2%2B37%5E2%2B43%5E2%29 58.5 thereabouts?
cross was good; i can wolf the other one for simplicities sake too
determinant of the vector matrix on 1 is 43, with any luck i recalled that stuff right
woowww thank you soo soo much!! :)
do we know if i was right? lol