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s3a
 4 years ago
Question about equation of plane, parametric equations and stuff like that:
http://f.imgtmp.com/HIhr6.jpg
Help would be GREATLY appreciated!
s3a
 4 years ago
Question about equation of plane, parametric equations and stuff like that: http://f.imgtmp.com/HIhr6.jpg Help would be GREATLY appreciated!

This Question is Closed

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0personally id create 2 vectors and cross them for the normal vector

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0can you type up the points for me, its hard to keep track of them

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0that's to get the first part?

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0P(4,6,2) and Q(8,7,0), R(7,3,5)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0good, now what im gonna do is define 2 vectors by subtracting one point from the other 2

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0wait, first let me finish part 1

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0Q(8,7,0) R( 7, 3, 5)  P(4,6,2)  P(4,6,2)  <4, 1, 2> <11,9,3> these are 2 vectors that reside on your plane between your points

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0lets cross them for a normal vector <4, 1, 2> <11,9,3>  x = (318) = 15 y = (1222) = 10 z = (3611) = 25 <15,10,25> is the normal vector which we can scale down to work with  5 <3,2,5> looks good to me

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0now, given any point on the plane; they gave you 3 to play with; we can construct the equation as such: 3(xPx)2(yPy)5(zPz)=0

s3a
 4 years ago
Best ResponseYou've already chosen the best response.02 secs, i was searching for something. now i can read properly.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0id use a simple point like (8,7,0) 3(x8)2(y7)5(z0)=0 3x+242y145z=0 3x2y5z+10=0 if i did it right that should be a match to your 3 points

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0ok so <3,2,5> is the normal vector and 3(xPx)2(yPy)5(zPz)=0 is from dot producting it?

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0ya i get that part now thank you. :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0gotta dbl chk my plane equation first, im prone to error at my age :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0so line PQ ... let me see

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0its a vector addition of P and Q right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327363860012:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0vector subtraction that is and the points themselvs act as defining the vectors

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0i just pictured like a toddler helping me on the other side :P

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0and sorry technical issues make it hard to respond fast here

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0so, PQ, i did above = <4,1,2> and this needs to be scaled to any length to create the line t<4,1,2> now all we have to do is attach it to either P or Q

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0i'm guessing your older rather than younger

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the best thing about today is that im one step closer to death :)

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0there is a comma between P and Q if that matters.

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0lol ... well eat healthy, etc

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0using 8,7,0 to anchor our line vector to we get: x = 8 + 4t y = 7 + 1t z = 0 + 2t should be the parametric stuff

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0if you plug in P for the x y z parts you should come out to t being the same for all parametrics

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0P=4,6,2 4 = 8 +4t 4 = 4t t = 1 7+1 = 6 0+2 = 2... that works for me :)

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0ok so you used Q to anchor and P works too. just confirmed.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0'sok, this computers getting slow as well

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0now the next one is perp to L and hits R

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0i didn't get what you did when you found a value for t and why you did it.

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0also, i don't recommend you use CRT. rather use LCD screens because they don't harm your eyes or are negligible in comparison. plasmas make radiation that dissipates before harming you so it's acceptable but i'd go with lcd anyways.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0since im anchored to Q and it has to go thru P then some value of "t" has to remain the same for each parametric in order to come up with the P values. I solved for Px in place of x to see if we can get a t that worked

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0when t=1 we get Px so i just subbed in t=1 for the others to see if they matched Py and Pz

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0if we anchored to P, then we would have used Q to test it out with :)

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0so what about the last part?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the last part I believe uses this line vector as a normal vector of this other plane; and this other plane has to hit R so we should just place Rx Ry Rz in the plane equation

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327364753446:dw

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0passing through means parallel but more precise?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0sooo, n<4,1,2>, calibrate with R(x,y,z) 4(xRx)+1(yRy)+2(zRz)=0 expanded of course

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0we want a plane perp to L, not parallel

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0which means L is our norm for this perp plane we need a point on that plane to anchor to, they say use R

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0makes sense since a point R is given :P

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0yeah, it was what (7,3,5) right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.04(x7)+1(y3)+2(z5)=0 4x28+y3+2z10=0 4x+y+2z10283=0 4x+y+2z41=0 maybe?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0im quick for an old man lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0im sure well be going over these in calc3 this term.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0trying to get me a masters in math before i die :)

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0go for it lol and eat healthy!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0:) ill try. good luck

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0we got the part 3 right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0pretty confident its good. the line vector from part 2 is our normal, and we anchored it with pointR; unless i missed the multiplication and adding parts :) that happens

s3a
 4 years ago
Best ResponseYou've already chosen the best response.0I'm at part three if you're going to help.
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