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anonymous
 4 years ago
Find the perimeter and area of each parallelogram. Round to the nearest tenth. Help
anonymous
 4 years ago
Find the perimeter and area of each parallelogram. Round to the nearest tenth. Help

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jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1Where is the parallelogram?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327364287076:dw

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1does it say anything about it being a rhombus?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1you made a mark in the lower right hand corner to denote a right angle, but you clearly have a 45 degree angle to the left of that, so which one is it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's what the book picture is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327364747193:dw

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1oh ok, one sec

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1the problem here is that this has to be a rhombus because if it wasn't then we'd be missing information (namely the base side that runs parallel to the ground), so double check to make sure that nothing is missing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if u can do it Show Work plz

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1are you familiar with trigonometry?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nope Only Alg and Geo

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1We can cut that parallelogram in half along that dashed line to get those two triangles We can then find the base b through the formula b = x/sqrt(2) where x is the hypotenuse In this case, x = 4, so the base is b = 4/sqrt(2) = 2.828 So the perimeter is P = 2*4 + 2*2.828 P = 13.656 So the perimeter is roughly 13.656 meters And the area of one triangle is A = (bh)/2 A = (2.828*2.828)/2 A = 8/2 A = 4 which means that the area of the parallelogram is 2*4 = 8 square meters

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1hw will get annoying definitely

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Willing to help wit all? 919 2028even

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1i'm afraid i don't have enough time, which one is really bugging you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk lol how long do u have

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1about 10 min or so

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok can u do some if u can

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1alright, which one do you want me to do?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0srry if i seem a pain in the A$$

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1No you're not a pain at all. # 11 This is a square. And the formula for the perimeter is P = 4s P = 4*5.4 P = 21.6 So the perimeter is 21.6 cm and the formula for the area is A = s^2 A = (5.4)^2 A= 5.4*5.4 A= 29.16 So the area of the square is 29.16 square cm

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1Last one and then I have to go # 12 Perimeter: P = 2*15+2*10 P = 30+20 P = 50 So the perimeter is 50 inches Area: A = bc*sin(theta) A = 10*15*sin(45) A = 150*0.70710678 A = 106.066017 So the area is roughly 106.066017 square inches
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