A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Find the equation of the quadratic that has xintercepts f(2)=0 and f(6)=0 in vertex form.
anonymous
 4 years ago
Find the equation of the quadratic that has xintercepts f(2)=0 and f(6)=0 in vertex form.

This Question is Closed

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2vertex x is half way between intercepts

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2so its at least got vertex on the x=2 axis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would i set it up then

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then how would I find the y

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2err, i think its +k for standard usage

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but how would i figure out k and the slope?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2without any other information; your pretty much at a stand still; there is a whole family of equations to fit this

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2if k is negative; make a + and f(x) = a(x+2)^2  k or the other way around since the vertex needs to be on the oterside of the opening end f(x) a(x+2)^2 + k

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1327365880607:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2anything but zeros for k and a should work, and make sure they gots opposite signs

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one sec let me test it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but whats the slope then?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2hmmm, i just tested a few on the wolf, my thoughts need some refinement :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2ok, try this; make k equal to half the distance between intercepts; in this case 4 should work for i trial run

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2.... recalculating lol we are sitting at 4; so if x=4 x^2 = 16 .... lets try 16 hope this aint to confusing yet

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2http://www.wolframalpha.com/input/?i=y%3D%28x%2B2%29%5E2++16

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2that one hit, i knew one of my ideas had to stick ;)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1327366276767:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2a simpler way would have been to construct an equation form the zeros: a(x+6)(x2)=0 but it wouldnt have been in vertex form

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thats ok, at least we found it :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.