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anonymous

  • 5 years ago

limit as x approaches 0 of (sin 5x)/7x?

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  1. anonymous
    • 5 years ago
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    I've considered multiply the numerator by 5x/5x so that sin x will become 1 as x approaches zero...but doesn't the problem then become 5x/7x and they both go to zero?

  2. myininaya
    • 5 years ago
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    \[\lim_{x \rightarrow 0}\frac{\sin(5x)}{5x} =1\] right? so how do we get this in our problem? \[\frac{5}{7}\lim_{x \rightarrow 0}\frac{\sin(5x)}{5x}\]

  3. cathyangs
    • 5 years ago
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    wouldn't there be no limit? *confuzzled* O.o

  4. myininaya
    • 5 years ago
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    \[\frac{5}{7}(1)=\frac{5}{7}\]

  5. anonymous
    • 5 years ago
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    Sorry, is there an intermediate step missing?

  6. TuringTest
    • 5 years ago
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    You can verify that myininaya is right very quickly if you know L'hospital's rule.

  7. myininaya
    • 5 years ago
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    all i did was multiply 5/5 @ josh

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