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anonymous
 5 years ago
limit as x approaches 0 of (sin 5x)/7x?
anonymous
 5 years ago
limit as x approaches 0 of (sin 5x)/7x?

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JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.1what's the limit as u > 0 of (sin u)/u

JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.1right. So think about trying to rewrite your equation in that form. Hint: the final answer is not 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am hopeful that I can multiply the numerator by 5x/5x. Then I can cancel out the leftover x in the numerator with the x in the denominator (5x/7x, where the x's cancel ) and have 5/7?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks...this is very humbling...haven't done algebra in years and I'm about a week into a calculus course. You've been very helpful twice now.

JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.1I don't even remember the first time, but I'm glad I have been. Keep at it. It's fun and intellectually very satisfying.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I asked about deltaepsilon proofs earlier in the day. I am studying very hard. Thanks again.
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