## anonymous 4 years ago find f`(x) for sqroot (x^(2)+4) some how i got x which i believe to be the wrong answer

1. anonymous

$\sqrt{x ^{2}+4}$ here is what it looks like

2. anonymous

$f'(x)=2x/(2(x^2+4))$

3. amistre64

sqrt = ^1/2

4. anonymous

oh thats right

5. anonymous

so it would be x^2/2?

6. amistre64

$(x^2+4)^{1/2}$ $\frac{1}{2}(x^2+4)^{1/2-2/2}*(x^2+4)'$ $\frac{1}{2}(x^2+4)^{1/2-2/2}*2x$

7. anonymous

thank you both

8. amistre64

forgot to actually do the 1/2 - 2/2 lol

9. amistre64

$\frac{1}{2}(x^2+4)^{1/2-2/2}*2x$ $\frac{2}{2}x(x^2+4)^{-1/2}$ $x(x^2+4)^{-1/2}=\frac{x}{\sqrt{x^2+4}}$

10. anonymous

well i got x because i have horrible algebra skills :D

11. anonymous

so who know that these could be done a on the calculator