Let f(x)=5x^2. Find a value A such that the average rate of change of f(x) from 1 to A equals 60.

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Let f(x)=5x^2. Find a value A such that the average rate of change of f(x) from 1 to A equals 60.

Mathematics
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the average rate of change is just (f(A) - f(1))/(A-1)
i know!
im getting the wrong answer for some reason though

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and im getting frustrated
\[\frac{5a^2-5.1^2}{a-1}=60\] \[5a^2-5=60(a-1)\] \[5a^2-5=60a-60\] \[5a^2-60a-5+60=0\] \[5(a^2-120a+11)=0\]
5.1?
\[a=\frac{1}{2}(12\pm\sqrt{12^2-4(11)})\]
its easier for me to get to the . then the *
\[\frac{5a^2-5(1)^2}{a-1}=60=> \frac{5(a^2-1)}{a-1}=60\] \[=>\frac{5(a-1)(a+1)}{a-1}=60 => 5(a+1)=60=> a+1=12\]
pfft!! thats cheating, and only gets one of them :)
ITS 11!!!!!!!!!!!!!!! O MY GOD!!!!!!!!!!!!!!!!!!!!!!!!
144-44 = 100 sqrt100 = 10 12 +- 10 /2 /2 6 +- 5 = 1 and 11?
cant be 1 so that leaves 11, yeah
a cannot be 1 dear lol
lol
i was getting to that :)
so my way gets all the possible values of A lol
not the complex ones :P
shhh lets not go there lol

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