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anonymous

  • 5 years ago

Let f(x)=5x^2. Find a value A such that the average rate of change of f(x) from 1 to A equals 60.

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  1. amistre64
    • 5 years ago
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    the average rate of change is just (f(A) - f(1))/(A-1)

  2. anonymous
    • 5 years ago
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    i know!

  3. anonymous
    • 5 years ago
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    im getting the wrong answer for some reason though

  4. anonymous
    • 5 years ago
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    and im getting frustrated

  5. amistre64
    • 5 years ago
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    \[\frac{5a^2-5.1^2}{a-1}=60\] \[5a^2-5=60(a-1)\] \[5a^2-5=60a-60\] \[5a^2-60a-5+60=0\] \[5(a^2-120a+11)=0\]

  6. anonymous
    • 5 years ago
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    5.1?

  7. amistre64
    • 5 years ago
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    \[a=\frac{1}{2}(12\pm\sqrt{12^2-4(11)})\]

  8. amistre64
    • 5 years ago
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    its easier for me to get to the . then the *

  9. myininaya
    • 5 years ago
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    \[\frac{5a^2-5(1)^2}{a-1}=60=> \frac{5(a^2-1)}{a-1}=60\] \[=>\frac{5(a-1)(a+1)}{a-1}=60 => 5(a+1)=60=> a+1=12\]

  10. amistre64
    • 5 years ago
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    pfft!! thats cheating, and only gets one of them :)

  11. anonymous
    • 5 years ago
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    ITS 11!!!!!!!!!!!!!!! O MY GOD!!!!!!!!!!!!!!!!!!!!!!!!

  12. amistre64
    • 5 years ago
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    144-44 = 100 sqrt100 = 10 12 +- 10 /2 /2 6 +- 5 = 1 and 11?

  13. amistre64
    • 5 years ago
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    cant be 1 so that leaves 11, yeah

  14. myininaya
    • 5 years ago
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    a cannot be 1 dear lol

  15. myininaya
    • 5 years ago
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    lol

  16. amistre64
    • 5 years ago
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    i was getting to that :)

  17. myininaya
    • 5 years ago
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    so my way gets all the possible values of A lol

  18. amistre64
    • 5 years ago
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    not the complex ones :P

  19. myininaya
    • 5 years ago
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    shhh lets not go there lol

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