## anonymous 4 years ago 3^x = (1/9)^3 What is the value of x?

1. anonymous

$3^x=(\frac19)^3$ $3^x=(9^{-1})^3=9^{-3}=(3^2)^{-3}=3^{-6}$ x=-6

2. anonymous

How did you get the 3^2?