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Mami_Garcia01
Group Title
HELPPP!!!
A science teacher has a supply of 5% hydrochloric acid and a supply of 65% hydrochloric acid (HCl). How much of each solution should the teacher mix together to get 42 mL of 45% HCl for an experiment? (1 point)
The teacher will need 14 mL of the 5% solution and 28 mL of the 65% solution.
The teacher will need 28 mL of the 5% solution and 14 mL of the 65% solution.
The teacher will need 14 mL of the 5% solution and 14 mL of the 65% solution.
The teacher will need 28 mL of the 5% solution and 28 mL of the 65% solution.
 2 years ago
 2 years ago
Mami_Garcia01 Group Title
HELPPP!!! A science teacher has a supply of 5% hydrochloric acid and a supply of 65% hydrochloric acid (HCl). How much of each solution should the teacher mix together to get 42 mL of 45% HCl for an experiment? (1 point) The teacher will need 14 mL of the 5% solution and 28 mL of the 65% solution. The teacher will need 28 mL of the 5% solution and 14 mL of the 65% solution. The teacher will need 14 mL of the 5% solution and 14 mL of the 65% solution. The teacher will need 28 mL of the 5% solution and 28 mL of the 65% solution.
 2 years ago
 2 years ago

This Question is Closed

mathmate Group TitleBest ResponseYou've already chosen the best response.1
Let x=vol. of 65%, then 42x = vol. of 5% Solve for x in: 0.65x+0.05(42x) = 42*0.45
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
x + y = 42 .5x + .65y = 42(.45)
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
You can eliminate the ones where the mL amount don't add up to 42 mL
 2 years ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
And from the two that remain, choose the choice that requires more 65% than 5%, since 45% is closer to 65% than 5%.
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Bro, how do you even find stuff like this from a year ago?
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
Thanks! :)
 one year ago
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