Calculus Help: Show that ln(y)=arctan(x) is a solution to the differential equation (1+x^2)y"+(2x-1)y'=0 I'm totally lost need help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Calculus Help: Show that ln(y)=arctan(x) is a solution to the differential equation (1+x^2)y"+(2x-1)y'=0 I'm totally lost need help!

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

From ln(y)=arcxtan(x), raise to power of e e^(ln(y))=e^(arctan(x)) y=e^arctan(x) now differentiate y to get y', and differentiate twice to get y". Substitute in the given equation's LHS to show that after simplification, the LHS = 0 (for any value of x).
Hint: you will need the chain rule to do the differentiations.
Thank you so much mathmate! you're a lifesaver :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

You're welcome! :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question