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√c (3 + 2√5) and √6 (7√3 + 6) Please help???

Mathematics
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is that a c in front?
its asking for the square root of 3 then(3+2√5) and then the other question
@ satellite

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Other answers:

The left :/
):
What are we suppose to do here?
Multiply and Simplify
Multiply/Distribute in this case, and simplify
I got the first one, just need help with the second
Y dont you retype the question?
It isnt so clear
\[\sqrt{3} (3+2 \sqrt{5}) \sqrt{6}(7 \sqrt{3}+6)?\]
we are finding product right?
\[√6(7√3 + 6)\] thats the one i still need help on
myinaya it itwo separate equations
distributing and simplifying
\[\sqrt{6}(7 \sqrt{3}+6)\]
\[\sqrt{6} \cdot 7 \sqrt{3}+\sqrt{6} \cdot 6 \]
i use distributive property there
a(b+c)=ab+ac
\[7 \sqrt{6} \sqrt{3}+6 \sqrt{6}\] \[7 \sqrt{2 \cdot 3} \sqrt{3}+6 \sqrt{6}\]
\[7 \sqrt{2} \sqrt{3} \sqrt{3}+6 \sqrt{6}\]
is the "c" a "3"??
\[7 \sqrt{2}(3)+6 \sqrt{6}=7(3) \sqrt{2}+6 \sqrt{6}=21 \sqrt{2}+6 \sqrt{6}\]
\[ \sqrt{6}(7 \sqrt{3}+6) = 21\sqrt{2} +6\sqrt{6} \]
Thank you guys so much!!
Distributive property holds because they are rationals.

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