anonymous
  • anonymous
√c (3 + 2√5) and √6 (7√3 + 6) Please help???
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
is that a c in front?
anonymous
  • anonymous
its asking for the square root of 3 then(3+2√5) and then the other question
anonymous
  • anonymous
@ satellite

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anonymous
  • anonymous
The left :/
anonymous
  • anonymous
):
anonymous
  • anonymous
What are we suppose to do here?
anonymous
  • anonymous
Multiply and Simplify
anonymous
  • anonymous
Multiply/Distribute in this case, and simplify
anonymous
  • anonymous
I got the first one, just need help with the second
anonymous
  • anonymous
Y dont you retype the question?
anonymous
  • anonymous
It isnt so clear
myininaya
  • myininaya
\[\sqrt{3} (3+2 \sqrt{5}) \sqrt{6}(7 \sqrt{3}+6)?\]
myininaya
  • myininaya
we are finding product right?
anonymous
  • anonymous
\[√6(7√3 + 6)\] thats the one i still need help on
anonymous
  • anonymous
myinaya it itwo separate equations
anonymous
  • anonymous
distributing and simplifying
myininaya
  • myininaya
\[\sqrt{6}(7 \sqrt{3}+6)\]
myininaya
  • myininaya
\[\sqrt{6} \cdot 7 \sqrt{3}+\sqrt{6} \cdot 6 \]
myininaya
  • myininaya
i use distributive property there
myininaya
  • myininaya
a(b+c)=ab+ac
myininaya
  • myininaya
\[7 \sqrt{6} \sqrt{3}+6 \sqrt{6}\] \[7 \sqrt{2 \cdot 3} \sqrt{3}+6 \sqrt{6}\]
myininaya
  • myininaya
\[7 \sqrt{2} \sqrt{3} \sqrt{3}+6 \sqrt{6}\]
anonymous
  • anonymous
is the "c" a "3"??
myininaya
  • myininaya
\[7 \sqrt{2}(3)+6 \sqrt{6}=7(3) \sqrt{2}+6 \sqrt{6}=21 \sqrt{2}+6 \sqrt{6}\]
anonymous
  • anonymous
\[ \sqrt{6}(7 \sqrt{3}+6) = 21\sqrt{2} +6\sqrt{6} \]
anonymous
  • anonymous
Thank you guys so much!!
anonymous
  • anonymous
Distributive property holds because they are rationals.

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