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mathhasproblems

√c (3 + 2√5) and √6 (7√3 + 6) Please help???

  • 2 years ago
  • 2 years ago

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  1. satellite73
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    is that a c in front?

    • 2 years ago
  2. LoveYou*69
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    its asking for the square root of 3 then(3+2√5) and then the other question

    • 2 years ago
  3. LoveYou*69
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    @ satellite

    • 2 years ago
  4. mathhasproblems
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    The left :/

    • 2 years ago
  5. LoveYou*69
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    ):

    • 2 years ago
  6. FoolForMath
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    What are we suppose to do here?

    • 2 years ago
  7. LoveYou*69
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    Multiply and Simplify

    • 2 years ago
  8. LoveYou*69
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    Multiply/Distribute in this case, and simplify

    • 2 years ago
  9. LoveYou*69
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    I got the first one, just need help with the second

    • 2 years ago
  10. Pippa
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    Y dont you retype the question?

    • 2 years ago
  11. Pippa
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    It isnt so clear

    • 2 years ago
  12. myininaya
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    \[\sqrt{3} (3+2 \sqrt{5}) \sqrt{6}(7 \sqrt{3}+6)?\]

    • 2 years ago
  13. myininaya
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    we are finding product right?

    • 2 years ago
  14. LoveYou*69
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    \[√6(7√3 + 6)\] thats the one i still need help on

    • 2 years ago
  15. Pippa
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    myinaya it itwo separate equations

    • 2 years ago
  16. LoveYou*69
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    distributing and simplifying

    • 2 years ago
  17. myininaya
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    \[\sqrt{6}(7 \sqrt{3}+6)\]

    • 2 years ago
  18. myininaya
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    \[\sqrt{6} \cdot 7 \sqrt{3}+\sqrt{6} \cdot 6 \]

    • 2 years ago
  19. myininaya
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    i use distributive property there

    • 2 years ago
  20. myininaya
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    a(b+c)=ab+ac

    • 2 years ago
  21. myininaya
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    \[7 \sqrt{6} \sqrt{3}+6 \sqrt{6}\] \[7 \sqrt{2 \cdot 3} \sqrt{3}+6 \sqrt{6}\]

    • 2 years ago
  22. myininaya
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    \[7 \sqrt{2} \sqrt{3} \sqrt{3}+6 \sqrt{6}\]

    • 2 years ago
  23. satellite73
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    is the "c" a "3"??

    • 2 years ago
  24. myininaya
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    \[7 \sqrt{2}(3)+6 \sqrt{6}=7(3) \sqrt{2}+6 \sqrt{6}=21 \sqrt{2}+6 \sqrt{6}\]

    • 2 years ago
  25. FoolForMath
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    \[ \sqrt{6}(7 \sqrt{3}+6) = 21\sqrt{2} +6\sqrt{6} \]

    • 2 years ago
  26. LoveYou*69
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    Thank you guys so much!!

    • 2 years ago
  27. FoolForMath
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    Distributive property holds because they are rationals.

    • 2 years ago
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