mathhasproblems
√c (3 + 2√5) and √6 (7√3 + 6) Please help???



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anonymous
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is that a c in front?

LoveYou*69
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its asking for the square root of 3 then(3+2√5) and then the other question

LoveYou*69
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@ satellite

mathhasproblems
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The left :/

LoveYou*69
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):

FoolForMath
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What are we suppose to do here?

LoveYou*69
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Multiply and Simplify

LoveYou*69
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Multiply/Distribute in this case, and simplify

LoveYou*69
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I got the first one, just need help with the second

Pippa
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Y dont you retype the question?

Pippa
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It isnt so clear

myininaya
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\[\sqrt{3} (3+2 \sqrt{5}) \sqrt{6}(7 \sqrt{3}+6)?\]

myininaya
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we are finding product right?

LoveYou*69
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\[√6(7√3 + 6)\] thats the one i still need help on

Pippa
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myinaya it itwo separate equations

LoveYou*69
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distributing and simplifying

myininaya
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\[\sqrt{6}(7 \sqrt{3}+6)\]

myininaya
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\[\sqrt{6} \cdot 7 \sqrt{3}+\sqrt{6} \cdot 6 \]

myininaya
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i use distributive property there

myininaya
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a(b+c)=ab+ac

myininaya
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\[7 \sqrt{6} \sqrt{3}+6 \sqrt{6}\]
\[7 \sqrt{2 \cdot 3} \sqrt{3}+6 \sqrt{6}\]

myininaya
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\[7 \sqrt{2} \sqrt{3} \sqrt{3}+6 \sqrt{6}\]

anonymous
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is the "c" a "3"??

myininaya
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\[7 \sqrt{2}(3)+6 \sqrt{6}=7(3) \sqrt{2}+6 \sqrt{6}=21 \sqrt{2}+6 \sqrt{6}\]

FoolForMath
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\[ \sqrt{6}(7 \sqrt{3}+6) = 21\sqrt{2} +6\sqrt{6} \]

LoveYou*69
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Thank you guys so much!!

FoolForMath
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Distributive property holds because they are rationals.