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anonymous

  • 4 years ago

A jar contains $31.50 in nickels and quarters. There are 178 coins in the jar. How many quarters are in the jar?

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  1. anonymous
    • 4 years ago
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    \[.25x+.05(178-x)=31.50\]

  2. anonymous
    • 4 years ago
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    put x = number of quarters, which have a total value of .25x, and since there are 178 coins total if there are x quarters there are 178 - x nickels which have a total value of .05(178-x)

  3. Hero
    • 4 years ago
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    I always end up forgetting a variable or something.

  4. anonymous
    • 4 years ago
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    add them up and get there combined value \[.25x+.05(178-x)=31.50\]

  5. anonymous
    • 4 years ago
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    it looked good to me!

  6. Hero
    • 4 years ago
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    Satellite, how do you avoid making typing mistakes?

  7. Hero
    • 4 years ago
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    What I meant to write was: n + q = 178 .05n + .25q = 31.50 The first time I forgot the q in the second equation. That's why I deleted it.

  8. mathmate
    • 4 years ago
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    178 coins in quarters (0.25$) and nickels (0.05$) are worth $31.50. If you don't have a calculator, nor pen and paper, this is how you would do it: 178 quarters are worth $44.50, that's $13 too much. In changing a quarter for a nickel, we reduce by 0.25-0.05=$0.20. So we would change $13/0.02=65 quarters for nickels. So we have 65 nickels and 178-65=113 quarters.

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