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anonymous

  • 4 years ago

cg^3+27c Factor Help Please

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  1. anonymous
    • 4 years ago
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    what can you GCF out of both terms?

  2. anonymous
    • 4 years ago
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    c

  3. anonymous
    • 4 years ago
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    right so now you have c(g^3+27). now you need to set it up ( )( ). what are you going to put in the front of the parenthesis?

  4. anonymous
    • 4 years ago
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    by front i mean the first spot in the template c(____ _____)(_____ _____)

  5. anonymous
    • 4 years ago
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    i am really not sure how to figure that part out??

  6. anonymous
    • 4 years ago
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    ok. so you want the variable in the first spot in each set of parenthesis (it's not a "law" but it keeps it cleaner). so, because you have an odd exponent that you cant split up evenly, one gets g^2 while the other gets g. make sense?

  7. anonymous
    • 4 years ago
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    yes i got it

  8. anonymous
    • 4 years ago
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    so now what does your template look like?

  9. anonymous
    • 4 years ago
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    c(g^2______)(g_____)

  10. anonymous
    • 4 years ago
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    right. now we need to split up 27 so that when you multiply the two numbers together, you get 27. so what are factors of 27

  11. anonymous
    • 4 years ago
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    p and 3

  12. anonymous
    • 4 years ago
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    9 sorry not p

  13. anonymous
    • 4 years ago
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    also, the two numbers should add up to the middle term…in this case 0. so we need to find numbers that multiply to 27 but add to zero.

  14. anonymous
    • 4 years ago
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    so is it 27 and 1 or 27 and 0

  15. anonymous
    • 4 years ago
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    ok. i have a question. what math are you in because this is not the (___ ___) (___ ___) setup that we had. it's (___ ___) (___ ___ ___). this might take longer to explain

  16. anonymous
    • 4 years ago
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    math 035

  17. anonymous
    • 4 years ago
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    what grade is that?

  18. anonymous
    • 4 years ago
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    i go to a community college the name of the class is fundamental of algebra 2

  19. anonymous
    • 4 years ago
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    ok. sorry i wasnt trying to be creepy or anything. its just that we covered this in class today

  20. anonymous
    • 4 years ago
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    no its fine

  21. anonymous
    • 4 years ago
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    so now we are looking at the sum or difference of two cubes…which makes a lot more sense, as the cube root of both these terms is "pretty"

  22. anonymous
    • 4 years ago
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    so the GCF is still c, but now we are looking at the setup of a^3+b^3=(a+b)(a^2-ab+b^2) otherwise known as the S.O.P. method. the first sign in the parenthesis stays the Same as the original problem the second sign is Opposite as the original, and the third is ALWAYS Positive.

  23. anonymous
    • 4 years ago
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    if a and b represent the original terms in the equation, what fills in the parenthesis?

  24. anonymous
    • 4 years ago
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    ok. you left but ill finish the problem in case you come back later so you can see how its done.

  25. anonymous
    • 4 years ago
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    the first part is just the original problem because your a=g and your b=3 a=g and b=3 so your second part is (g+3) a^2 is g^2 and ab is 3g and b^2 is 9 so your third part is (g^2-3g+9) put it all together and your final answer is (g+3)(g^2-3g+9)

  26. anonymous
    • 4 years ago
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    hope this helped

  27. anonymous
    • 4 years ago
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    thank you so much. my internet mess up on me. I felt so rude cause i know u were really trying to help me. Thanks so much :)

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