anonymous
  • anonymous
cg^3+27c Factor Help Please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what can you GCF out of both terms?
anonymous
  • anonymous
c
anonymous
  • anonymous
right so now you have c(g^3+27). now you need to set it up ( )( ). what are you going to put in the front of the parenthesis?

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anonymous
  • anonymous
by front i mean the first spot in the template c(____ _____)(_____ _____)
anonymous
  • anonymous
i am really not sure how to figure that part out??
anonymous
  • anonymous
ok. so you want the variable in the first spot in each set of parenthesis (it's not a "law" but it keeps it cleaner). so, because you have an odd exponent that you cant split up evenly, one gets g^2 while the other gets g. make sense?
anonymous
  • anonymous
yes i got it
anonymous
  • anonymous
so now what does your template look like?
anonymous
  • anonymous
c(g^2______)(g_____)
anonymous
  • anonymous
right. now we need to split up 27 so that when you multiply the two numbers together, you get 27. so what are factors of 27
anonymous
  • anonymous
p and 3
anonymous
  • anonymous
9 sorry not p
anonymous
  • anonymous
also, the two numbers should add up to the middle term…in this case 0. so we need to find numbers that multiply to 27 but add to zero.
anonymous
  • anonymous
so is it 27 and 1 or 27 and 0
anonymous
  • anonymous
ok. i have a question. what math are you in because this is not the (___ ___) (___ ___) setup that we had. it's (___ ___) (___ ___ ___). this might take longer to explain
anonymous
  • anonymous
math 035
anonymous
  • anonymous
what grade is that?
anonymous
  • anonymous
i go to a community college the name of the class is fundamental of algebra 2
anonymous
  • anonymous
ok. sorry i wasnt trying to be creepy or anything. its just that we covered this in class today
anonymous
  • anonymous
no its fine
anonymous
  • anonymous
so now we are looking at the sum or difference of two cubes…which makes a lot more sense, as the cube root of both these terms is "pretty"
anonymous
  • anonymous
so the GCF is still c, but now we are looking at the setup of a^3+b^3=(a+b)(a^2-ab+b^2) otherwise known as the S.O.P. method. the first sign in the parenthesis stays the Same as the original problem the second sign is Opposite as the original, and the third is ALWAYS Positive.
anonymous
  • anonymous
if a and b represent the original terms in the equation, what fills in the parenthesis?
anonymous
  • anonymous
ok. you left but ill finish the problem in case you come back later so you can see how its done.
anonymous
  • anonymous
the first part is just the original problem because your a=g and your b=3 a=g and b=3 so your second part is (g+3) a^2 is g^2 and ab is 3g and b^2 is 9 so your third part is (g^2-3g+9) put it all together and your final answer is (g+3)(g^2-3g+9)
anonymous
  • anonymous
hope this helped
anonymous
  • anonymous
thank you so much. my internet mess up on me. I felt so rude cause i know u were really trying to help me. Thanks so much :)

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