anonymous
  • anonymous
A 1.7 × 10 3 kg elevator carries a maximum load of 876.7 kg. A constant frictional force of 4.3 × 10 3 N retards the elevator’s motion upward. What minimum power must the motor deliver to lift the fully loaded elevator at a constant speed 3.45 m/s? The acceleration due to gravity is 9.81 m/s 2 . Answer in units of kW
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
First, let's define power, so we know what we have and what we will need to determine. \[P = F \cdot v\] We are given the velocity at which the elevator travels, now all we need to do it determine the forces involved. I spot only two, gravitation and friction. \[F = F_g + F_f = m \cdot g + F_f\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.