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anonymous
 4 years ago
Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 33.0 and half the distance at 80.0 . On her return trip, she drives half the time at 33.0 and half the time at 80.0 .
What is Julie's average speed on the way to Grandmother's house?
anonymous
 4 years ago
Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 33.0 and half the distance at 80.0 . On her return trip, she drives half the time at 33.0 and half the time at 80.0 . What is Julie's average speed on the way to Grandmother's house?

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0reprint already answered

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0...unless someone wants to plug in the numbers for you that is http://openstudy.com/study#/updates/4f1e3b56e4b04992dd24a260

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(33.0+80.0)/2=56.5 from this formula ==> average speed = (V1+V2+V3+...)/n

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1Very importantly, what alismart has written is false in general. For example, if I drive  30 km in one hour (v1 = 30 km/hr) followed by  30 km in the next 1/2 hour (v2 = 60 km/hr) then my average speed from first principles is Average speed = (distance)/(time) = (60 km)/(1.5 hours) = 40 km/hr Using alismart's formula, the average speed would be \[ \frac{30 + 60}{2} = 45 \] which is wrong.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then if you want to bring distance the complete formula will be : x=distance ==>

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327423607110:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0''V'' can be ''m/s'' and distance will be meter
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