anonymous
  • anonymous
estimate the limit by substituting smaller and smaller values of h, use radians. h---0 cos(h)-1/h I know you are suppos to use mumbers like .01 .001 .1 etc to then find a common limity, jsut confused on the rad part. thank you
Mathematics
schrodinger
  • schrodinger
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TuringTest
  • TuringTest
Your calculator probably has at least two ways to write angles: degrees and radians\[360^{\circ}=2\pi \text{radians}\]You really should know about radians in general if you have taken trigonometry, but as far as the question is concerned just make sure your calculator is in radian mode and not degrees.
TuringTest
  • TuringTest
...radians are another unit for angles besides degrees basically (a much more mathematically logical unit to use as well!)
anonymous
  • anonymous
yeah i got ya on that, i was just confused if I should use like a radian measure that I know like cos(1pi/6 ) equaling sqrt3/2 or what not to get it to be .001

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anonymous
  • anonymous
i jsut dont know what rad to get to equal .001
TuringTest
  • TuringTest
the question is probably not asking you to find when the answer is 0.001, that doesn't help you much with the limit you are probably just plugging in h=0.001
anonymous
  • anonymous
ok i got ya ill try that
TuringTest
  • TuringTest
...but if you wanted to know for what value of h we had the function equal to 0.001 you would solve\[\cos h-\frac1 h=0.001\]which I can't really think how to do offhand
TuringTest
  • TuringTest
...there isn't much sense to that though
campbell_st
  • campbell_st
the limit will tend to be undefined.... because as you substitute smaller values of h 1/h becomes extemely large.... look at the problem in 2 parts.... cos(h) will approach 1....
anonymous
  • anonymous
^^ correct plugged it into the graph calculator. It is 0 or undefined. Thank you for the help guys!
TuringTest
  • TuringTest
the limit should never be zero, it should be \[-\infty\]or undefined as campbell said. welcome!

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