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anonymous
 4 years ago
Can somebody help me relearn combinations and permutations? I haven't used them in years and I'm taking the GRE in the next month!
anonymous
 4 years ago
Can somebody help me relearn combinations and permutations? I haven't used them in years and I'm taking the GRE in the next month!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you have a specific question? it is easy enough to write a formula, but that might not be helpful

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, I don't have any specific questions. It's just that I can't just memorize the formulas without fully understanding them.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok well if you want "permutations" like arranging 4 people in 4 chairs, the number of ways to do it is \[4!=4\times 3\times 2\] and that is simple enough to understand by the "counting principle" 4 choices for the first seat 3 for the second 2 for the third and no choice for the last one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, I understand that.. But then once I get to combinations, I get confused.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.khanacademy.org/video/permutations?playlist=Precalculus

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Watch that video and the ones that follow.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok well if you understand that, then we are on our way. suppose then you want to know how many committees of 4 people you can make out of a total of ten people. then again by the counting principle you have \[10\times 9\times 8\times 7\] ways to do it, but that counts too many because it counts all the permutations as different. so you have to divide by the number of ways you can permute the 4 people, and we just said what that way, namely 4!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the answer would be \[\frac{10\times 9\times 8\times 7}{4\times 3\times 2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what about if repetitions are allowed?
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