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anonymous
 4 years ago
Find the area of the solid obtained by rotating the region bounded by the given curves about the specified line.
y=x^3, y=x, x>0
anonymous
 4 years ago
Find the area of the solid obtained by rotating the region bounded by the given curves about the specified line. y=x^3, y=x, x>0

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campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0find the point of intersections of the 2 curves....by equating the curves.... i.e \[x = x^3\] or \[x^3  x =0 \] which gives \[x(x^2 1)=0\] the points of intersection will be x = 0 and x = 1 (x = 1 not considered because of initial conditions. then the problem is \[V = \pi \int\limits_{0}^{1} (x^3  x)^2 dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i thought you took the larger radius  the smaller radius. \[(xx ^{3})\]?

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0The area between is rotated.... dw:1327394267382:dw the shape is like the horn of a trumpet if in doubt... include absolute value symbols around the integral...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0rotation about line y=x
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