How do you: Use f(x) = 3x -5 and g(x) = 2 - x^2 to evaluate the following expressions: 1. (a) f(g(0)) (b) g(f(0)) 2. (a) (f ` g) (-2) (b) g(g(3))

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How do you: Use f(x) = 3x -5 and g(x) = 2 - x^2 to evaluate the following expressions: 1. (a) f(g(0)) (b) g(f(0)) 2. (a) (f ` g) (-2) (b) g(g(3))

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find g(0)... by substituting x = 0 into g(x)... then substitute that answer into f(x0 1. (a) f(g(0)) g(0) = 2 f(2) = 3 x 2 - 5 = 1 (b) similar to (a) but start with f(0) 2. (a) looks like finding the derivative of f(x) = 3 not sure on the notation (b) find g(3)... then substitute that answer into g(x) again
why does g(o)= 2?
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