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moongazer
 4 years ago
Find the radius and the center of the circle.
Just check my answer.
moongazer
 4 years ago
Find the radius and the center of the circle. Just check my answer.

This Question is Closed

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1(xCx)^2+(yCy)^2=r^2

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.22x^2 + 2y^2  2x + 2y + 7 = 0 My answer is : c(1/2,1/2) r= \[\sqrt{7/2}\]

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.2Am I right? Cause I am having doubt that my answer is wrong because I have a negative radius

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.12x^2 + 2y^2  2x + 2y + 7 = 0 2x^2  2x + 2y^2 + 2y + 7 = 0 2(x^2  x) + 2(y^2 +y) = 7 2(x^2  x +(1/2)^2) + 2(y^2 +y+(1/2)^2) = 7 + 1 2(x1/2)^2 + 2(y+1/2) = 6 its quite possible that this cannot produce a real circle; just becasue something has some numbers thrown about doesnt make it sensible :) lets chk the wolf

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1and make sure that aint spose to be a 7 instead

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=2x%5E2+%2B+2y%5E2++2x+%2B+2y+%2B+7+%3D+0 as is its right, but no circle

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.0Check for typos: Could the question be 2x^2 + 2y^2  2x + 2y = 7 or 2x^2 + 2y^2  2x + 2y  7 = 0

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.2That's why I am having doubts with my answer. :) Maybe I just copied the text wrong.

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.2If it is 7 will the answers be c(1/2,1/2) r=\[\sqrt{7/2}\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1if 7 then we get r^2 = 8 center: (1/2, 1/2)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.11/2 yeah, but r=sqrt(8) = 2sqrt(2)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1did that wrong somehow, radius is 2 according to the wolf

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=2x%5E2+%2B+2y%5E2++2x+%2B+2y++7+%3D+0

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[r^2=7+2(1/2)^2+2(1/2)^2\]

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.2how did it became x = 3/2, x = 5/2 ???

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i see what i did; we divide off the 2 and get 8/2 = 4 sqrt(4) = 2

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1your responses arent making sense to me

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[2(x^2  x +(1/2)^2) + 2(y^2 +y+(1/2)^2) = 7 + 1\] \[2(x(1/2))^2 + 2(y+(1/2))^2 = 8\] \[(x(1/2))^2 + (y+(1/2))^2 = 4\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1those are points on the circle that the wolf handed out

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.22(x^2  x +(1/2)^2) + 2(y^2 +y+(1/2)^2) = 7 + 1 Why did you add one on the right side of the equation?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1becasue we add a total of 1 to the left side 2(1/2)^2 + 2(1/2)^2 = 1

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.12x^2  2x +2(1/2)^2 + 2y^2 +2y +2(1/2)^2) = 7 + 1 might be easier to see that way

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i dont divide off the "2" right away which might be a difference in our computing techniques

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.2ohh ok, I forgot adding the numbers that I added on the left side to the right side. That's why I got confused. :) Anyway, I divided the equation directly to "2" but I still got the right answer. :)
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