anonymous
  • anonymous
what is the limit of sin^2 x/ x^2 as x approaches infinity
Mathematics
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anonymous
  • anonymous
what is the limit of sin^2 x/ x^2 as x approaches infinity
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
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ash2326
  • ash2326
sin x's range is [-1,1] sin^2 x range will be [0,1] now x^2 as x--->∞is ∞ so sin^2 x/ x^2 = finite quantity/ infinite quantity = 0
ricardovg
  • ricardovg
what is the limit of sin^2 x/ x^2 as x approaches infinity sin^2 x/ x^2 = sin(x).sin(x)/x.x = (sin(x)/x).(sin(x)/x) limit of 1/x as x approaches to infinity is equals 0 => 0.sin(x) = 0 answer is 0

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anonymous
  • anonymous
what if the denominator is just x
ash2326
  • ash2326
then also, we'll get 0, it'd still be finite/infinite, therfore 0

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