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anonymous
 4 years ago
a wooden block of mass 8 kg is tied to a string attatched to the bottom of the tank.In equilibrium the block is completely immersed in water. if relative density of wood is 0.8 and g=10m/s^2 then what is the value of tension in the string?
anonymous
 4 years ago
a wooden block of mass 8 kg is tied to a string attatched to the bottom of the tank.In equilibrium the block is completely immersed in water. if relative density of wood is 0.8 and g=10m/s^2 then what is the value of tension in the string?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hey jamesj pleese help

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3There are three forces acting on the block of wood F_g = force of gravity (down) F_b = force of buoyancy (up) F_s = force from the string (down) The block is in equilibrium hence the sum of the three is zero. Use that to solve for F_s. The magnitude of F_s is the tension in the string.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow i am extremely convinced

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but for more convinciation can u pleese solve the problem for me

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3No ... I want you to take the next steps. What are expressions for \[ F_g \] and \[ F_b \] ?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3F_g is particularly easy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so u dono the expressions?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3I do know. Of course. But I want you to learn by doing, not watching.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3To find F_b, go back to first principles and definitions The buoyant force is equal to the weight of water displaced. hence you need to find the weight of water displaced. The find the weight of water displaced, you'll need to find the volume of water displaced and multiply it by the density of water. Then to find the volume of water displaced ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0buoyant force=weight of water displaced

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3Ok, yes, where m here is the mass of the water displaced

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3We use rho, \( \rho \) for density. Hence you have by definition \[ \rho_{water} = \frac{m_{water}}{V_{water}} \] where V is volume. Hence \[ m_{water} = \rho_{water}.V_{water} \] Now find \( V_{water} \). It must be equal to \( V_{block} \). Hence you have to find \( V_{block} \). Use the same density principle. That's why the density of wood was given to you in the problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so wat's the use of relative density

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3Tell me first what's the equation of the volume of the block?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3Hence \[ m_{water} = \rho_{water}.V_{water} \] \[ = \rho_{water} . V_{block} \] because the volume of water displaced must equal the volume of the block \[ = \rho_{water}.\frac{m_{block}}{\rho_{block}} \ \ \ \ \text{ by definition of density } \] \[ = \frac{\rho_{water}}{\rho_{block}}. m_{block} \] See what to do now?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i cant understand the last equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k thanks for yor help iam really happy with the presence of u

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3what don't you understand about the last equation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no other guy was able to answer my qusetion

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'll send u a frnd request in face book

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what is your fb username and i am nt big enough to misuse it

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3By definition \[ \rho_{block}/\rho_{water} \] is the relative density of the block, i.e., is equal to 0.8 Therefore \[ m_{water} = \rho_{water}/\rho_{block}.m_{block} \] \[ = (\rho_{block}/\rho_{water})^{1}.m_block \] \[ = (0.8)^{1}.m_block \] \[ = (5/4).m_block \] \[ = (5/4).(8 \ kg) \] \[ = 10 \ kg \] Now I want you to make an effort to finish the problem yourself, as I've now shown you 90% of it.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3I should have written \[ m_{block} \] not \[ m_block \]

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3I'm going to help someone else with a question. Try and figure it out while I'm gone. I'll keep an eye on what's going on over here.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k by the way pleese tell yor fb username

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3No, I don't do that, sorry.
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