anonymous
  • anonymous
a wooden block of mass 8 kg is tied to a string attatched to the bottom of the tank.In equilibrium the block is completely immersed in water. if relative density of wood is 0.8 and g=10m/s^2 then what is the value of tension in the string?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
any 1 pleeeese help
anonymous
  • anonymous
hey jamesj pleese help
JamesJ
  • JamesJ
There are three forces acting on the block of wood F_g = force of gravity (down) F_b = force of buoyancy (up) F_s = force from the string (down) The block is in equilibrium hence the sum of the three is zero. Use that to solve for F_s. The magnitude of F_s is the tension in the string.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

JamesJ
  • JamesJ
Make sense?
anonymous
  • anonymous
wow i am extremely convinced
anonymous
  • anonymous
but for more convinciation can u pleese solve the problem for me
JamesJ
  • JamesJ
No ... I want you to take the next steps. What are expressions for \[ F_g \] and \[ F_b \] ?
JamesJ
  • JamesJ
F_g is particularly easy
anonymous
  • anonymous
is f_g is mg?
JamesJ
  • JamesJ
yes
anonymous
  • anonymous
so u dono the expressions?
JamesJ
  • JamesJ
I do know. Of course. But I want you to learn by doing, not watching.
anonymous
  • anonymous
k pleese wait
JamesJ
  • JamesJ
To find F_b, go back to first principles and definitions The buoyant force is equal to the weight of water displaced. hence you need to find the weight of water displaced. The find the weight of water displaced, you'll need to find the volume of water displaced and multiply it by the density of water. Then to find the volume of water displaced ...
anonymous
  • anonymous
buoyant force=weight of water displaced
anonymous
  • anonymous
i.e F_b=mg
JamesJ
  • JamesJ
Ok, yes, where m here is the mass of the water displaced
anonymous
  • anonymous
ya
anonymous
  • anonymous
so now can u solve
JamesJ
  • JamesJ
We use rho, \( \rho \) for density. Hence you have by definition \[ \rho_{water} = \frac{m_{water}}{V_{water}} \] where V is volume. Hence \[ m_{water} = \rho_{water}.V_{water} \] Now find \( V_{water} \). It must be equal to \( V_{block} \). Hence you have to find \( V_{block} \). Use the same density principle. That's why the density of wood was given to you in the problem.
anonymous
  • anonymous
so wat's the use of relative density
JamesJ
  • JamesJ
Tell me first what's the equation of the volume of the block?
anonymous
  • anonymous
of cousre it is m/d
anonymous
  • anonymous
d is the density
JamesJ
  • JamesJ
Hence \[ m_{water} = \rho_{water}.V_{water} \] \[ = \rho_{water} . V_{block} \] because the volume of water displaced must equal the volume of the block \[ = \rho_{water}.\frac{m_{block}}{\rho_{block}} \ \ \ \ \text{ by definition of density } \] \[ = \frac{\rho_{water}}{\rho_{block}}. m_{block} \] See what to do now?
anonymous
  • anonymous
i cant understand the last equation
anonymous
  • anonymous
k thanks for yor help iam really happy with the presence of u
JamesJ
  • JamesJ
what don't you understand about the last equation.
anonymous
  • anonymous
no other guy was able to answer my qusetion
anonymous
  • anonymous
i'll send u a frnd request in face book
anonymous
  • anonymous
what is your fb username and i am nt big enough to misuse it
JamesJ
  • JamesJ
By definition \[ \rho_{block}/\rho_{water} \] is the relative density of the block, i.e., is equal to 0.8 Therefore \[ m_{water} = \rho_{water}/\rho_{block}.m_{block} \] \[ = (\rho_{block}/\rho_{water})^{-1}.m_block \] \[ = (0.8)^{-1}.m_block \] \[ = (5/4).m_block \] \[ = (5/4).(8 \ kg) \] \[ = 10 \ kg \] Now I want you to make an effort to finish the problem yourself, as I've now shown you 90% of it.
JamesJ
  • JamesJ
I should have written \[ m_{block} \] not \[ m_block \]
anonymous
  • anonymous
wow wow wo o
JamesJ
  • JamesJ
I'm going to help someone else with a question. Try and figure it out while I'm gone. I'll keep an eye on what's going on over here.
anonymous
  • anonymous
k by the way pleese tell yor fb username
JamesJ
  • JamesJ
No, I don't do that, sorry.

Looking for something else?

Not the answer you are looking for? Search for more explanations.