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anonymous
 4 years ago
How do I expand
(2g+2)^8
anonymous
 4 years ago
How do I expand (2g+2)^8

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you know binomial theorem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmmm... it is much long and complicated. Do you know what is factorial?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here is the link. and try to understand. i will surely help you. http://www.intmath.com/seriesbinomialtheorem/4binomialtheorem.php

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If I were to expand (3t)^3 is it 3^3+3(3^2t)+3(3t^2)t^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no... did you use it correctly?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think so. what did i do wrong?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here your brackets are wrong. they should look like this. 3(3^2)t and 3(3)t^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you want to learn basic of binomial theorem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok. it will take much time. let us start. do you know the formula (a+b)^2=a^2+2ab+b^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0good. it is also a binomial theorem. Notice that here power two indicates that when we expand our formula, we get one more term than the no. of exponent. Here exponent is 2 while when we expanded then we got 3 terms.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0similarly, I hope you know the formula (a+b)^3=a^3+3a^2b+3ab^2+b^3 here exponent is 3 while expanded terms are 4. This implies that expanded terms will always be one more than the exponent. Now is it clear?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oo I think I get it now. Thank you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0welcome. ok now make a step ahead. here is binomial formula. \[(a+b)^{n}=C _{0}^{n}a ^{n}+C _{1}^{n}a ^{n1}b+C _{2}^{n}a ^{n2}b ^{2}.....\] Where C stands for combination. in general this combination is written as, \[C _{r}^{n}=n!/(r!(nr)!)\] now in above formula is constantly increasing, r=0,r=1,r=2.......
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