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anonymous

  • 4 years ago

Can someone please solve and explain this word problem? "A rectangular painting measures 12 inches by 16 inches and is surrounded by a frame of uniform width around the four edges. The perimeter of the rectangle formed by the painting and its frame is 72 inches. Determine the width of the frame."

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  1. amistre64
    • 4 years ago
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    this is the pool problem again

  2. amistre64
    • 4 years ago
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    x+12+x = width x+16+x = length

  3. amistre64
    • 4 years ago
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    perimeter is 72 72/2 = 36 hmmm

  4. amistre64
    • 4 years ago
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    nah, just add up twice the length and width and equal it out to 72

  5. amistre64
    • 4 years ago
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    4x+24+4x+32 = 72 if i see it right; where x = width of frame

  6. Mertsj
    • 4 years ago
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    |dw:1327424303620:dw|

  7. amistre64
    • 4 years ago
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    x+6+x+8 = 18 2x = 4 x = 2?

  8. Mertsj
    • 4 years ago
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    P=72=2(16+2x)+2(12+2x) 72=32+4x+24+4x 72=56+8x 16=8x x=2=the width of the frame

  9. anonymous
    • 4 years ago
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    this answer is x=2...my book said that the top border and left border were x though, not the little squares in the corners....

  10. Mertsj
    • 4 years ago
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    x is the width of the border and the border is the same width all the way around so if the little squares in the corner are x inches long and x inches wide, then that is what the entire border is.

  11. anonymous
    • 4 years ago
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    oh! ok that makes total sense. thanks for helping! :D

  12. Mertsj
    • 4 years ago
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    |dw:1327426111410:dw|

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