limit as x approaches 0 of (1-cos5x)/7x^2 ?

limit as x approaches 0 of (1-cos5x)/7x^2 ?

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No, how is the form of this 1/2? I know that 1-cosax / ax is 0, but that doesn't seem helpful.

One way or another you need to use the derivative of cos x. Do you know l'Hopital's rule?

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