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anonymous
 5 years ago
how do you complete the square
anonymous
 5 years ago
how do you complete the square

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0depends on the context. are you trying to solve a quadratic equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they are the same thing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah then you want to find the vertex by comleting the square. i.e. you want to write \[y=ax^2+bx+c\] as \[y=a(xh)^2+k\] right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^2 +bx+c=x^2+bx+(b/2)^2(b/2)^2+c=(x+b/2)^2+c(b/2)^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here is an easy method with an example. the vertex is always where \[x=\frac{b}{2a}\] so if i see \[y=x^26x+5\] i know the first coordinate of the vertex will be \[\frac{6}{2(1)}=3\] and the second coordinate will be what i get when i replace x by 3 namely 4 so i know it is \[y=x^26x+5=(x3)^24\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here is another method. if you have \[y=ax^2+bx+c\] you can rewrite as \[y=a(x^2+\frac{b}{a}x)+c\] and then write \[y=a(x+\frac{b}{2a})^2+c\frac{b^2}{4a}\] but that seems unnecessarily complicated
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