anonymous
  • anonymous
help with calclulus
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
can you explain to me what was done? I undertsnad what they did with the infinity but I dont get how they added a 2 to the integrand
1 Attachment
campbell_st
  • campbell_st
if you look at the intergrand they have put 1/2 out the front and the numerator is 2y...... remember 1/2 x 2y = y.....

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anonymous
  • anonymous
LOL but why didthey do that?
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anonymous
  • anonymous
sorry abt the attachment but there seems to be a bug
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campbell_st
  • campbell_st
its to make the numerator look like the derivative of the denominator.... which would suggest the solution would be a ln function
campbell_st
  • campbell_st
the solution might be... let u = y^2 du = 2y \[1/2\int\limits_{0}^{b} du/(u^2 + 1)\] which is tan^(-1)
campbell_st
  • campbell_st
oops should read 1/2 tan^(-1) (u) then re substitute 1/2 tan^(-1) (y^2)
anonymous
  • anonymous
Thanks that was clear campbell :D That is exactly what I wanted to know

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