anonymous
  • anonymous
find b given that: A(4,10) and B(b,7) are 5 units apart. How can i solve it ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
distance formula\[5=\sqrt(4-b)^2+(10-7)^2\] that sqrt should be over the whole right side
anonymous
  • anonymous
then solve for b
anonymous
  • anonymous
b=8 or b=0 there are 2 possibilities.

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anonymous
  • anonymous
So it would be 5 = 4-b + 9?
anonymous
  • anonymous
could you show how you got your results?
anonymous
  • anonymous
please cause i have 4 problems like this
anonymous
  • anonymous
the (4-b) is still square and the right side should still be under the sqrt
anonymous
  • anonymous
yeah
anonymous
  • anonymous
\[5=\sqrt((4-b)^2+(10-7)^2)\] \[25=(4-b)^2+9\] subtract 9\[16=(4-b)^2\] take the squareroot, and remember that when taking the squareroot you have to use the negative and positive\[\pm4=4-b\]
anonymous
  • anonymous
can you complete from there? or want me to finish?
anonymous
  • anonymous
finish it please
anonymous
  • anonymous
sorry! im just a better learning seeing it out solved
anonymous
  • anonymous
so you have\[4=4-b \] subtract 4 and multiply by -1 to get rid of the negative \[0=b\] and you also have\[-4=4-b\] subtract 4\[-8=-b\] and multiply by -1 to get rid of the negative \[8=b\]
anonymous
  • anonymous
I don't mind. Everyone learns differently and I'm happy to help.
anonymous
  • anonymous
thank you but i have one more
anonymous
  • anonymous
the question is
anonymous
  • anonymous
A(b,b) is sqrt(18) units from its origin.
anonymous
  • anonymous
find b
anonymous
  • anonymous
the origin is at (0,0) so assuming the b is the same you have\[\sqrt18=\sqrt{(b-0)^2+(b-0)^2}\]
anonymous
  • anonymous
so\[\sqrt{18}=\sqrt{b^2+b^2}\] \[\sqrt{18}=\sqrt{2b^2}\]square both sides \[18=2b^2\]divide by 2 \[9=b^2\]take the square \[\pm3=b\]root

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