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tux
 4 years ago
What I am doing wrong?
integrate dx/(x^34x)
Rewrite denominator as x*(x^24) and then use integration by partial fractions.
(A/x) + (Bx+C)/(x^24)
1=A*(x^24)+(Bx+C)*x
A=1/4 B=1/4 C=0
After that I have to integrate 1/4*integral dx/x
Result is 1/4ln(x)
Second integral is (1/4*x)/(x^24)
As result I get 1/8*ln(x^24)
My final result is 1/4ln(x)+1/8*ln(x^24)+C
Is my result correct?
tux
 4 years ago
What I am doing wrong? integrate dx/(x^34x) Rewrite denominator as x*(x^24) and then use integration by partial fractions. (A/x) + (Bx+C)/(x^24) 1=A*(x^24)+(Bx+C)*x A=1/4 B=1/4 C=0 After that I have to integrate 1/4*integral dx/x Result is 1/4ln(x) Second integral is (1/4*x)/(x^24) As result I get 1/8*ln(x^24) My final result is 1/4ln(x)+1/8*ln(x^24)+C Is my result correct?

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slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.2x^2  4 = (x  2)(x + 2)

slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.2So it becomes A/x + B/(x+2) + C/(x2)

tux
 4 years ago
Best ResponseYou've already chosen the best response.0When I take x(x2)(x+2) then A=1/4 B=1/8 C=1/8 and result is \[1/4*\ln(x)+1/8\ln(x2)+1/8\ln(x+2)\]
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