## anonymous 5 years ago A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . shorter diagonal =

if you draw it you see the shorter diagonal is from U to S so find that distance$d=\sqrt(6-3)^2+(1-3)^2$ sqrt should be over whole right side