## anonymous 4 years ago How do you find the integral of 1/(x^2 + (3/4) )

1. anonymous

x/(x^3/3+3/4x)

2. anonymous

Note that the derivative of $\tan^{-1} x$ is $1/(x^2+1)$ I think you can figure out the solution from here.

3. anonymous

Cal1994, that's a little incorrect. The answer is $(2/\sqrt{3})\tan^{-1} ((2x)/\sqrt{3})$

4. anonymous

realised after i posted it because on that problem to get the derivative you would have had to do the quotent rule

5. anonymous

Ok, thanks. :)