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anonymous

  • 5 years ago

Use quadratic formula to solve for y 3x^2- 2(sqrt3)xy +y^2 +6(sqrt3)x -2y -40=0

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  1. myininaya
    • 5 years ago
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    so we can put y in terms of x?

  2. myininaya
    • 5 years ago
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    \[(1)y^2+(-2 \sqrt{3}x-2)y+(3x^2+6 \sqrt{3}x-40)=0\]

  3. myininaya
    • 5 years ago
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    \[\text{ where }a=1, b=-2 \sqrt{3}-2 , c=3x^2+6 \sqrt{3} x-40\]

  4. myininaya
    • 5 years ago
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    \[y=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

  5. anonymous
    • 5 years ago
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    well the option that is closest to what i get when i plug those in is y=1+sqrt3(x) +/- sqrt(-4sqrt3(x) =41)

  6. myininaya
    • 5 years ago
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    \[y=\frac{-(-2 \sqrt{3}-2) \pm \sqrt{(-2 \sqrt{3}-2)^2-4(1)(3x^2+6 \sqrt{3}x-40)}}{2(1)}\]

  7. myininaya
    • 5 years ago
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    this is crazy lookin' lol

  8. myininaya
    • 5 years ago
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    \[y=\frac{2 \sqrt{3} +2 \pm \sqrt{4(3)-2(-2 \sqrt{3} (2))+2^2-12x^2-24 \sqrt{3} x+160}}{2}\]

  9. anonymous
    • 5 years ago
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    haha yes i know! that is what i got when i plugged them in. However, i have multiple choice, and t hat is not an option. \[y= 1+ \sqrt{3}x \pm \sqrt{-4\sqrt{3}x +41}\]

  10. anonymous
    • 5 years ago
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    this is the only similar option

  11. myininaya
    • 5 years ago
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    \[y=\frac{2 \sqrt{3} +2 \pm \sqrt{12+8 \sqrt{3}+4-12x^2-24 \sqrt{3} x+160}}{2}\]

  12. anonymous
    • 5 years ago
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    idk its not one of my options :(

  13. myininaya
    • 5 years ago
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    \[y=\frac{2 \sqrt{3}+2 \pm \sqrt{-12x^2-24 \sqrt{3}x+176+8 \sqrt{3}}}{2}\] i'm still simplying i'm just showing my steps

  14. myininaya
    • 5 years ago
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    simplifying*

  15. anonymous
    • 5 years ago
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    oh okay! sorry!

  16. myininaya
    • 5 years ago
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    \[y=\frac{2 \sqrt{3}+2 \pm \sqrt{4} \sqrt{-3x^2-6 \sqrt{x} +44+2 \sqrt{3}}}{2}\]

  17. myininaya
    • 5 years ago
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    \[y=\frac{2 \sqrt{3} +2 \pm 2 \sqrt{-3x^2-6 \sqrt{x}+44+2 \sqrt{3}}}{2}\]

  18. myininaya
    • 5 years ago
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    notice each term has the common factor 2

  19. myininaya
    • 5 years ago
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    \[y=\frac{ \sqrt{3}+1 \pm 1 \sqrt{-3x^2-6 \sqrt{x}+44+2 \sqrt{3}}}{1}\] \[y= \sqrt{3}+1 \pm \sqrt{-3x^2-6 \sqrt{x}+44+2 \sqrt{3}}\]

  20. myininaya
    • 5 years ago
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    oops i'm missing x in my b term

  21. myininaya
    • 5 years ago
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    :(

  22. myininaya
    • 5 years ago
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    i have to do this on paper lol

  23. myininaya
    • 5 years ago
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    can you give me a sec?

  24. anonymous
    • 5 years ago
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    its alright! of course i can! do you think when you are done you could help me with another similar problem?

  25. myininaya
    • 5 years ago
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    ok i got it

  26. myininaya
    • 5 years ago
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    i'm gonna scan it

  27. anonymous
    • 5 years ago
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    ok:)

  28. myininaya
    • 5 years ago
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  29. myininaya
    • 5 years ago
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    which is what you thought gj

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  30. anonymous
    • 5 years ago
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    yes! thank you so much

  31. myininaya
    • 5 years ago
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    that is weird the file posted twice

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  32. myininaya
    • 5 years ago
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    how many times do you see the file?

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  33. myininaya
    • 5 years ago
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    it keeps posting :(

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  34. anonymous
    • 5 years ago
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    like 5 at least haha

  35. myininaya
    • 5 years ago
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    ok i have to do something post your new question on the left ok and if i get back i will look at it

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  36. anonymous
    • 5 years ago
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    okay! i will.

  37. myininaya
    • 5 years ago
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    :) fun problem by the way

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  38. anonymous
    • 5 years ago
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    haha yes it was! thanks for your help!

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