PHYSICS QUESTION. helpppp with this last problem.

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PHYSICS QUESTION. helpppp with this last problem.

Physics
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An object's mass is 50 KG. 1- what is its potential energy relative to the ground if its height is 20 meters above the earth? 2- What is its potential energy relative to the ground if the objet is raised from 20m to 100 m? 3- what is the gain in potential energy? 4- What is the gain in total mechanical energy ? (assuming the object at rest at both 20 and 100 m)
5- What is the amount of work applied to the object to raise it from 20m to 100m? 6- what is the amount of force applied to raise it? 7- what is the weight of the object? 8 - why is the weight equal the force acting on the object lift it? 9 - what is the power of the machine used to do lifting if the process took 5s to complete?
What is the equation for potential energy?

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m * g * y
Correct. So what is the potential energy when y = 20?
So 1 = 9800 J and 2 = 39200J but with 3 i subract 39200 - 9800?
Yes, yes, and yes!
@nikkysterr: don't forget eashmore some medals for his help!
whooo ! alright but it confuses me when it comes to "object at rest"
For #4, total mechanical energy is the sum of potential and kinetic energies. If an object is at rest, what is it's kinetic energy?
0?
Correct. So what is the total mechanical energy?
Mechanical Energy is zero.
I'm having some internet trouble. Forgive me if my responses are delayed.
no problem i appreciate your help.
physics isnt my strongest subject.
Nope. Mechanical Energy (ME) is defined as such\[ME = KE + PE\]If KE is zero, we still need to account for PE.
so mechanical energy isnt zero?
Nope. It is equal to potential energy in this case.
Oh so the mechanical energy would be the Potential Energy?
for the amount of work how do i find the force?
i know i have the distance 80 [100-20]
but i need the force. to get the work.
Nope. To find the work, we can use the work-energy theorem which is defined as\[W = \Delta ME = \Delta KE + \Delta PE = \Delta PE\]
We will find the force from this value of work, using the definition of work you are thinking of. You're on the right track.
the work force is equal to the PE.
Work is equal to the same answer we got for number 3.
because i was thinking w = f times d. and force = mass times acceleration i
Now, from this value\[W = F \cdot y\]We can find the force from this expression, using the value from work obtained in number 5.
so it would be 9800J = f * 80?
Yes. I must leave now. I'll leave you with an outline of what to do: I must leave. I'll outline the solution to the remainder of the questions: 5. The amount of work comes from the definition of work I gave you earlier. \[W = \Delta U = \Delta KE + \Delta PE = \Delta PE\] 6. Comes from the other definition of work. \[W = F \cdot y\]We know the work from part 5, and the distance we move in y (100 - 20). We can solve for y. 7. Weight is equal to (mass)x(gravity) 8. Because we are not accelerating the object upwards in a true sense, we are just opposing gravity to lift the object. 9. \[P = {W \over t}\]
thank you so much for your help ! i appreciate it !

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