anonymous
  • anonymous
PHYSICS QUESTION. helpppp with this last problem.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
An object's mass is 50 KG. 1- what is its potential energy relative to the ground if its height is 20 meters above the earth? 2- What is its potential energy relative to the ground if the objet is raised from 20m to 100 m? 3- what is the gain in potential energy? 4- What is the gain in total mechanical energy ? (assuming the object at rest at both 20 and 100 m)
anonymous
  • anonymous
5- What is the amount of work applied to the object to raise it from 20m to 100m? 6- what is the amount of force applied to raise it? 7- what is the weight of the object? 8 - why is the weight equal the force acting on the object lift it? 9 - what is the power of the machine used to do lifting if the process took 5s to complete?
anonymous
  • anonymous
What is the equation for potential energy?

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anonymous
  • anonymous
m * g * y
anonymous
  • anonymous
Correct. So what is the potential energy when y = 20?
anonymous
  • anonymous
So 1 = 9800 J and 2 = 39200J but with 3 i subract 39200 - 9800?
anonymous
  • anonymous
Yes, yes, and yes!
JamesJ
  • JamesJ
@nikkysterr: don't forget eashmore some medals for his help!
anonymous
  • anonymous
whooo ! alright but it confuses me when it comes to "object at rest"
anonymous
  • anonymous
For #4, total mechanical energy is the sum of potential and kinetic energies. If an object is at rest, what is it's kinetic energy?
anonymous
  • anonymous
0?
anonymous
  • anonymous
Correct. So what is the total mechanical energy?
anonymous
  • anonymous
Mechanical Energy is zero.
anonymous
  • anonymous
I'm having some internet trouble. Forgive me if my responses are delayed.
anonymous
  • anonymous
no problem i appreciate your help.
anonymous
  • anonymous
physics isnt my strongest subject.
anonymous
  • anonymous
Nope. Mechanical Energy (ME) is defined as such\[ME = KE + PE\]If KE is zero, we still need to account for PE.
anonymous
  • anonymous
so mechanical energy isnt zero?
anonymous
  • anonymous
Nope. It is equal to potential energy in this case.
anonymous
  • anonymous
Oh so the mechanical energy would be the Potential Energy?
anonymous
  • anonymous
for the amount of work how do i find the force?
anonymous
  • anonymous
i know i have the distance 80 [100-20]
anonymous
  • anonymous
but i need the force. to get the work.
anonymous
  • anonymous
Nope. To find the work, we can use the work-energy theorem which is defined as\[W = \Delta ME = \Delta KE + \Delta PE = \Delta PE\]
anonymous
  • anonymous
We will find the force from this value of work, using the definition of work you are thinking of. You're on the right track.
anonymous
  • anonymous
the work force is equal to the PE.
anonymous
  • anonymous
Work is equal to the same answer we got for number 3.
anonymous
  • anonymous
because i was thinking w = f times d. and force = mass times acceleration i
anonymous
  • anonymous
Now, from this value\[W = F \cdot y\]We can find the force from this expression, using the value from work obtained in number 5.
anonymous
  • anonymous
so it would be 9800J = f * 80?
anonymous
  • anonymous
Yes. I must leave now. I'll leave you with an outline of what to do: I must leave. I'll outline the solution to the remainder of the questions: 5. The amount of work comes from the definition of work I gave you earlier. \[W = \Delta U = \Delta KE + \Delta PE = \Delta PE\] 6. Comes from the other definition of work. \[W = F \cdot y\]We know the work from part 5, and the distance we move in y (100 - 20). We can solve for y. 7. Weight is equal to (mass)x(gravity) 8. Because we are not accelerating the object upwards in a true sense, we are just opposing gravity to lift the object. 9. \[P = {W \over t}\]
anonymous
  • anonymous
thank you so much for your help ! i appreciate it !

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