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anonymous
 4 years ago
Please help me!! Ahh calculus
anonymous
 4 years ago
Please help me!! Ahh calculus

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0} \left[ x ^{2}\sin (1/x) \right]\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No limit. You can't divide by 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i tried that. it doesn't work like that my teacher said I was wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Answer is 0 Use the squeeze theroem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what is the squeeze theroem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It says that if you have three functions, and the middle function lies inbetween the upper and lower one, the limit of the middle function is above the lower and below the upper function. I didn't really understand it, seemed like common sense. Maybe someone can explain more fully to you.
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