1. anonymous

$\lim_{x \rightarrow 0} \left[ x ^{2}\sin (1/x) \right]$

2. anonymous

No limit. You can't divide by 0.

3. anonymous

i tried that. it doesn't work like that my teacher said I was wrong

4. anonymous

Does not exist.

5. anonymous

Answer is 0 Use the squeeze theroem

6. anonymous

what is the squeeze theroem

7. anonymous

It says that if you have three functions, and the middle function lies in-between the upper and lower one, the limit of the middle function is above the lower and below the upper function. I didn't really understand it, seemed like common sense. Maybe someone can explain more fully to you.