anonymous
  • anonymous
A particle moves along the x-axis so that its velocity at any time t > 0 is given by v(t)=(2π − 5)t −sin(πt) . A. Find the acceleration at any time t.
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

lalaly
  • lalaly
the acceleration is the rate of change of velocity, so acceleration is the derivative of velocity\[a=\frac{dv}{dt}=(2\pi -5)-\pi \cos \pi t\]
anonymous
  • anonymous
B. Find the minimum acceleration of the particle over the interval [0, 3]. (12 points) So to answer B, I make the derivative = 0?
lalaly
  • lalaly
to find the minimum acceleration of the particle, looking at 0≤t≤3 see that when t =0, the acceleration is at a minimum. so substitute t=0 in the equation of a

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Thanks, for C would I substitute 2 for t? C. Find the maximum velocity of the particle over the interval [0, 2].
anonymous
  • anonymous
?

Looking for something else?

Not the answer you are looking for? Search for more explanations.