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anonymous
 4 years ago
A particle moves along the xaxis so that its velocity at any time t > 0 is given by v(t)=(2π − 5)t −sin(πt) .
A. Find the acceleration at any time t.
anonymous
 4 years ago
A particle moves along the xaxis so that its velocity at any time t > 0 is given by v(t)=(2π − 5)t −sin(πt) . A. Find the acceleration at any time t.

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lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2the acceleration is the rate of change of velocity, so acceleration is the derivative of velocity\[a=\frac{dv}{dt}=(2\pi 5)\pi \cos \pi t\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0B. Find the minimum acceleration of the particle over the interval [0, 3]. (12 points) So to answer B, I make the derivative = 0?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2to find the minimum acceleration of the particle, looking at 0≤t≤3 see that when t =0, the acceleration is at a minimum. so substitute t=0 in the equation of a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks, for C would I substitute 2 for t? C. Find the maximum velocity of the particle over the interval [0, 2].
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