## anonymous 4 years ago Find the equation of the line that is parallel to the line 2x-3y=-4 containing the point (-5,3)

1. karatechopper

first you want to get it in slope intercept form

2. anonymous

ok

3. karatechopper

slope intercept form= y=mx+b

4. karatechopper

lets put this in slope intercept form! 2x-3y=-4 subtract 2x on both sides -3y=-2x-4 divide by negative 3 on both sides y-2/3x+4/3

5. karatechopper

mak that be y=2/3x+4/3

6. saifoo.khan

Ok, so we will start from solving that given line First of all, solve that line in the form of y=mx+c Where "m" is the slope. Note: Parallel line means same slope. 2x-3y=-4 Solve for y $3y = 2x +4$$y = \frac23x + \frac43$ Comparing this with y=mx+c Slope is "m", so slope we get is 2/3. Now insert the point given and the slope in the formula, (i.e. slope and (-5,2) $y-y_1 = m(x-x_1)$ $y - 2 = \frac23 (x-(-5))$ Im sure u can solve now! :)

7. karatechopper

so now lets use a formula called point slope form. do you know the formula for that?

8. anonymous

how do you get y-2?

9. saifoo.khan

It's given in the question, Point (-5,2)

10. anonymous

its (-5,3)

11. saifoo.khan

12. anonymous

$y−2=2/3(x−(−5))$ y=2/3x +5.33

13. saifoo.khan

i prefer writing that in fractions

14. anonymous

15. saifoo.khan

Nope.

16. anonymous

17. saifoo.khan

$y = \frac23 x+\frac{19}{3}$

18. anonymous

its not 19/3. (2/3)*5+2= 5.33

19. saifoo.khan

hold on..

20. anonymous

ok?

21. saifoo.khan

lol, u made a mistake, (2/3)5 + 3

22. anonymous

hahah wow. Thanks for catching that!

23. saifoo.khan

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