A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
lim h → 0 (f(2+h)f(2))/h
F(x)=x^2+1
anonymous
 4 years ago
lim h → 0 (f(2+h)f(2))/h F(x)=x^2+1

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04 and in a week you will do this problem in your head in two seconds by saying "the derivative of \[x^2+1\] is \[2x\] and \[2\times 2=4\] but you have not gotten there yet so you have some work to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Could you please show work on how to solve this using the equation, so I know for future refrences?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(2)=2^2+1=5\] \[f(2+h)=(2+h)^2+1=4+4h+h^2+1=5+4h+h^2\] \[f(2+h)f(2)=5+4h+h^25=4h+h^2\] \[\frac{f(2+h)f(2)}{h}=\frac{4h+h^2}{h}=\frac{h(4+h)}{h}=4+h\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now you can take the limit as h goes to zero and you get 4 for sure

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all steps are there, nothing left out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yw notice that the 5's add to zero. it will always work this way if the limit exists. because you have an h in the denominator, the only way for this limit to exist is if the constant goes and you have nothing but h's
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.