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anonymous

  • 5 years ago

Solve for t using natural logarithms. 7e^6t=10e^5t

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  1. anonymous
    • 5 years ago
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    how?

  2. saifoo.khan
    • 5 years ago
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    Oh, wait.

  3. saifoo.khan
    • 5 years ago
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    Let me show it.

  4. anonymous
    • 5 years ago
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    thanks

  5. anonymous
    • 5 years ago
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    it says to round 3 decimals to prob not 0

  6. saifoo.khan
    • 5 years ago
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    \[\Large e^{6t} = \frac{10}{7} e^{5t}\]

  7. saifoo.khan
    • 5 years ago
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    This equation thing isnt workin. just a sec.

  8. anonymous
    • 5 years ago
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    okk

  9. saifoo.khan
    • 5 years ago
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    \[\Large 6t = \ln (\frac{10}{7} e^{5t})\]

  10. anonymous
    • 5 years ago
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    and from there?

  11. saifoo.khan
    • 5 years ago
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    Thinkin.

  12. anonymous
    • 5 years ago
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    thanks

  13. saifoo.khan
    • 5 years ago
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    wow, this is confusing.

  14. saifoo.khan
    • 5 years ago
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    Got it. :D

  15. anonymous
    • 5 years ago
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    yayyyy

  16. saifoo.khan
    • 5 years ago
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    \[\Large 6t = \ln (\frac{10}{7}) + \ln e^{5t}\] \[\Large 6t = \ln (\frac{10}{7}) + 5t\ln e\] \[\Large 6t = \ln (\frac{10}{7}) + 5t(1)\] \[\Large 6t = \ln (\frac{10}{7}) + 5t\] \[\Large 6t-5t = \ln (\frac{10}{7})\] \[\Large t = \ln(\frac{10}{7})\]

  17. anonymous
    • 5 years ago
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    sure?

  18. saifoo.khan
    • 5 years ago
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    100%.

  19. anonymous
    • 5 years ago
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    awesome! ill try it. thankss

  20. anonymous
    • 5 years ago
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    Wow, thanks so much :)

  21. saifoo.khan
    • 5 years ago
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    Welcome.

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