A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
P(EF') = P(E)  P(EF)
Is it true or false? if its false how?
anonymous
 4 years ago
P(EF') = P(E)  P(EF) Is it true or false? if its false how?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[P(E\cap F)=P(E)F(E\cap F^c)\]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no not F(EF') its P(EF')

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first of all by previous exercise we know that \[E=(E\cap F)\cup (E\cap F^c)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah that was as typo

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and since \[E\cap F\] and \[E\cap F^c\] are disjoint, the probability of their union is the sum of their probabilities, that is \[P((E\cap F)\cup (E\cap F^c))=P(E\cap F) +P (E\cap F^c)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0therefore since the sets are the same, you have \[P(E)=P(E\cap F) +P (E\cap F^c)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you think about what this says in english it is obvious. you are interested in the probability of E so you know you are in the set E. now if you are in E either you are in F or you are not in F those are the logical possibilities. so \[E=(E\cap F)\cup (E\cap F^c)\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.