anonymous
  • anonymous
\[\lim_{x \rightarrow 4}((1/(x-3))-(1-1))/(x-4) \] and the answer is not 0
Mathematics
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anonymous
  • anonymous
\[\lim_{x \rightarrow 4}((1/(x-3))-(1-1))/(x-4) \] and the answer is not 0
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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campbell_st
  • campbell_st
is there a typo in this question..?
anonymous
  • anonymous
nope
campbell_st
  • campbell_st
in the 2nd part there seems to be a missing bracket... (1 -1))/(x - 4)

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anonymous
  • anonymous
oh there is a typo it should be ((1/(x-3))-(1/1))/(x-4)
campbell_st
  • campbell_st
still an odd number of brackets... but I think you need the limit property \[\lim_{x \rightarrow a} f(x)- g(x) = \lim_{x \rightarrow a} f(x) - \lim_{a \rightarrow a} g(x)\]

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