The sum of three consecutive integers is 72. Find the integers.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

The sum of three consecutive integers is 72. Find the integers.

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

23+24+25=72
x x+1 x+2 are the consecutive integers x+(x+1) +(x+2)=72 3x+3=72 3x=69 x=23 x+1=24 x+2=25
There's a 'bad' or 'fast way of doing it...think about 3x20=60 and 3x30 = 90. We know the integers must be between 20 and 30 then. We need their units to sum to 12, and we can achieve this by looking at 3+4+5 hence the integers are 23, 24, 25. But Mertsj's way is most pleasing ;)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

The point being, \[3\times 20 \geq x + (x-1) + (x-2)\] for \[x \leq 20\] and \[3 \times 30 \leq y + (y+1)+(y+2)\] for \[y\geq 30\] so we know our sum must be of three consecutive numbers between 20 and 30, then it's just a case of playing with sums of units to get a 12..

Not the answer you are looking for?

Search for more explanations.

Ask your own question