Solve: 2r^2-11x+5=0
Thanks :)
p.s. explain?

- anonymous

Solve: 2r^2-11x+5=0
Thanks :)
p.s. explain?

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- anonymous

Do you know the quadratic formula?

- Hero

The variables should be the same, right?

- anonymous

Agreed.

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## More answers

- anonymous

Good eye.

- Hero

Good eye? It was blatantly obvious, lol :P

- anonymous

oh right! My teacher made a typo, lol. they should both be r's. and no, I don't remember anything from algebra 1! Which is bad :/

- Hero

How do you know they shouldn't both be x's?

- anonymous

well, letters don't really matter. whichever you replace, they would still be the same problem.
just different letters.

- anonymous

I think he's being humorous, sakigirl.

- anonymous

can someone just help me? lol. i'm kinda stuck on this question >_<

- Hero

2r^2-11r+5=0
2r^2-10r-1r+5 = 0
2r(r-5)-1(r-5) = 0
(r-5)(2r-1) = 0
r = 1/2
r = 5

- anonymous

Hero is right.

- Mimi_x3

You can also use the quadratic formula, which is faster i guess.
\[\large x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]

- Hero

Nope, I'm faster. The quad formula is whack.

- anonymous

Hahaha!

- Hero

Mimi uses it because she can't factor :P

- Mimi_x3

Nope, well..the using the quadratic you won't need to think much as to factor where you mgiht make stupid mistakes.

- Hero

Mimi, you forgot to put the line that protects your discriminant :P

- Mimi_x3

what line?

- Hero

The square root line.....(DUH) :P

- Mimi_x3

wtf..there's nothing wrong :/
You're confusing me :/

- Hero

lol, just teasing. Don't cry on me :P

- anonymous

HERO. one last question. i beg.

- Mimi_x3

Oh..gawd, confusing a poor kid that just woke up :'(

- Hero

Here we go again with the "poor little kid" retreat line you always pull :P

- Mimi_x3

You dont have the right to alternate my phrases i said "poor kid" NOT "poor little kid" :P

- Hero

poor kid = poor little kid
To me it's the exact same thing. A sympathy plea

- anonymous

kwell, I'm just gonna ask. 2c^2+c-10=0

- Hero

Mimi can use her quad form to help you

- Mimi_x3

Excuse me, its not a "sympathy plea" i never told you to be pity me. GOsh people these days who dont have common sense.

- anonymous

i don't remember crap about the quad form hah.

- Mimi_x3

Because Hero is unable to factor it :P

- Mimi_x3

\[\large c=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]
\[\large c=\frac{-(1)\pm\sqrt{(1)^{2}-4(2)(-10)}}{2(2)} \]

- Hero

2c^2+c-10=0
2c^2+5c-4c-10 = 0
c(2c+5)-2(2c+5) = 0
(2c+5)(c-2) = 0
c = -5/2, 2

- Hero

Mimi jinxed me.

- Mimi_x3

lol, i told you that you will make stupid mistakes :P
The factor method is such a FAIL!

- anonymous

Mimi made careless mistakes! :O

- Hero

Quad Form is an even bigger fail, especially when you depend on it so much Mimi :P

- Hero

I know about 5 different factor methods

- Hero

None of which include the dreaded quad form

- anonymous

how would you use the quad form on questions like 25m^2-64=0??

- Mimi_x3

What? You dont have the right to say that its a fail since i got it right in the first go, not like you who go it WRONG! EVen during exams it would be a waste of time to do it again :P

- anonymous

a.k.a binomials.

- Hero

25m^2 - 64 = 0
25m^2 = 64
m^2 = 64/25
m = sqrt{64/25}
m = plus or minus 8/5

- Mimi_x3

Btw, quadratic formula can only be used for ax^3+bx+c

- anonymous

Oh right, I totally knew that.

- Mimi_x3

ax^2*

- Hero

Yeah, the quad form is LIMITED

- Hero

While I was working hard to provide your solution sakigirl. Mimi, started making useless comments

- anonymous

hahah, forgetting the line of the square root. Oh silly her.

- Mimi_x3

I was trying to help her know a better method to solve it which is quicker. I was being nice

- Hero

I was being nicer :P

- Mimi_x3

whaat? forgettng the line of the square root?

- Hero

lol

- anonymous

Yeah! and Hero commented on it

- Hero

lol

- Mimi_x3

lol, sorry to say i think you should scroll up, i never make those carelless mistakes.

- Hero

you just made one, then auto corrected it. Putting ax^3 , then ax^2. Such silly mistakes :P

- Mimi_x3

its called a TYPO, you make stupid mistakes as well argh..i should never comment in questions that you are in anymore.

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