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anonymous

  • 4 years ago

Solve: 2r^2-11x+5=0 Thanks :) p.s. explain?

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  1. anonymous
    • 4 years ago
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    Do you know the quadratic formula?

  2. Hero
    • 4 years ago
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    The variables should be the same, right?

  3. anonymous
    • 4 years ago
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    Agreed.

  4. anonymous
    • 4 years ago
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    Good eye.

  5. Hero
    • 4 years ago
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    Good eye? It was blatantly obvious, lol :P

  6. anonymous
    • 4 years ago
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    oh right! My teacher made a typo, lol. they should both be r's. and no, I don't remember anything from algebra 1! Which is bad :/

  7. Hero
    • 4 years ago
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    How do you know they shouldn't both be x's?

  8. anonymous
    • 4 years ago
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    well, letters don't really matter. whichever you replace, they would still be the same problem. just different letters.

  9. anonymous
    • 4 years ago
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    I think he's being humorous, sakigirl.

  10. anonymous
    • 4 years ago
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    can someone just help me? lol. i'm kinda stuck on this question >_<

  11. Hero
    • 4 years ago
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    2r^2-11r+5=0 2r^2-10r-1r+5 = 0 2r(r-5)-1(r-5) = 0 (r-5)(2r-1) = 0 r = 1/2 r = 5

  12. anonymous
    • 4 years ago
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    Hero is right.

  13. Mimi_x3
    • 4 years ago
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    You can also use the quadratic formula, which is faster i guess. \[\large x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]

  14. Hero
    • 4 years ago
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    Nope, I'm faster. The quad formula is whack.

  15. anonymous
    • 4 years ago
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    Hahaha!

  16. Hero
    • 4 years ago
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    Mimi uses it because she can't factor :P

  17. Mimi_x3
    • 4 years ago
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    Nope, well..the using the quadratic you won't need to think much as to factor where you mgiht make stupid mistakes.

  18. Hero
    • 4 years ago
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    Mimi, you forgot to put the line that protects your discriminant :P

  19. Mimi_x3
    • 4 years ago
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    what line?

  20. Hero
    • 4 years ago
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    The square root line.....(DUH) :P

  21. Mimi_x3
    • 4 years ago
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    wtf..there's nothing wrong :/ You're confusing me :/

  22. Hero
    • 4 years ago
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    lol, just teasing. Don't cry on me :P

  23. anonymous
    • 4 years ago
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    HERO. one last question. i beg.

  24. Mimi_x3
    • 4 years ago
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    Oh..gawd, confusing a poor kid that just woke up :'(

  25. Hero
    • 4 years ago
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    Here we go again with the "poor little kid" retreat line you always pull :P

  26. Mimi_x3
    • 4 years ago
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    You dont have the right to alternate my phrases i said "poor kid" NOT "poor little kid" :P

  27. Hero
    • 4 years ago
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    poor kid = poor little kid To me it's the exact same thing. A sympathy plea

  28. anonymous
    • 4 years ago
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    kwell, I'm just gonna ask. 2c^2+c-10=0

  29. Hero
    • 4 years ago
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    Mimi can use her quad form to help you

  30. Mimi_x3
    • 4 years ago
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    Excuse me, its not a "sympathy plea" i never told you to be pity me. GOsh people these days who dont have common sense.

  31. anonymous
    • 4 years ago
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    i don't remember crap about the quad form hah.

  32. Mimi_x3
    • 4 years ago
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    Because Hero is unable to factor it :P

  33. Mimi_x3
    • 4 years ago
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    \[\large c=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \] \[\large c=\frac{-(1)\pm\sqrt{(1)^{2}-4(2)(-10)}}{2(2)} \]

  34. Hero
    • 4 years ago
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    2c^2+c-10=0 2c^2+5c-4c-10 = 0 c(2c+5)-2(2c+5) = 0 (2c+5)(c-2) = 0 c = -5/2, 2

  35. Hero
    • 4 years ago
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    Mimi jinxed me.

  36. Mimi_x3
    • 4 years ago
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    lol, i told you that you will make stupid mistakes :P The factor method is such a FAIL!

  37. anonymous
    • 4 years ago
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    Mimi made careless mistakes! :O

  38. Hero
    • 4 years ago
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    Quad Form is an even bigger fail, especially when you depend on it so much Mimi :P

  39. Hero
    • 4 years ago
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    I know about 5 different factor methods

  40. Hero
    • 4 years ago
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    None of which include the dreaded quad form

  41. anonymous
    • 4 years ago
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    how would you use the quad form on questions like 25m^2-64=0??

  42. Mimi_x3
    • 4 years ago
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    What? You dont have the right to say that its a fail since i got it right in the first go, not like you who go it WRONG! EVen during exams it would be a waste of time to do it again :P

  43. anonymous
    • 4 years ago
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    a.k.a binomials.

  44. Hero
    • 4 years ago
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    25m^2 - 64 = 0 25m^2 = 64 m^2 = 64/25 m = sqrt{64/25} m = plus or minus 8/5

  45. Mimi_x3
    • 4 years ago
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    Btw, quadratic formula can only be used for ax^3+bx+c

  46. anonymous
    • 4 years ago
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    Oh right, I totally knew that.

  47. Mimi_x3
    • 4 years ago
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    ax^2*

  48. Hero
    • 4 years ago
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    Yeah, the quad form is LIMITED

  49. Hero
    • 4 years ago
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    While I was working hard to provide your solution sakigirl. Mimi, started making useless comments

  50. anonymous
    • 4 years ago
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    hahah, forgetting the line of the square root. Oh silly her.

  51. Mimi_x3
    • 4 years ago
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    I was trying to help her know a better method to solve it which is quicker. I was being nice

  52. Hero
    • 4 years ago
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    I was being nicer :P

  53. Mimi_x3
    • 4 years ago
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    whaat? forgettng the line of the square root?

  54. Hero
    • 4 years ago
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    lol

  55. anonymous
    • 4 years ago
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    Yeah! and Hero commented on it

  56. Hero
    • 4 years ago
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    lol

  57. Mimi_x3
    • 4 years ago
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    lol, sorry to say i think you should scroll up, i never make those carelless mistakes.

  58. Hero
    • 4 years ago
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    you just made one, then auto corrected it. Putting ax^3 , then ax^2. Such silly mistakes :P

  59. Mimi_x3
    • 4 years ago
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    its called a TYPO, you make stupid mistakes as well argh..i should never comment in questions that you are in anymore.

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