anonymous
  • anonymous
Solve: 2r^2-11x+5=0 Thanks :) p.s. explain?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Do you know the quadratic formula?
Hero
  • Hero
The variables should be the same, right?
anonymous
  • anonymous
Agreed.

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anonymous
  • anonymous
Good eye.
Hero
  • Hero
Good eye? It was blatantly obvious, lol :P
anonymous
  • anonymous
oh right! My teacher made a typo, lol. they should both be r's. and no, I don't remember anything from algebra 1! Which is bad :/
Hero
  • Hero
How do you know they shouldn't both be x's?
anonymous
  • anonymous
well, letters don't really matter. whichever you replace, they would still be the same problem. just different letters.
anonymous
  • anonymous
I think he's being humorous, sakigirl.
anonymous
  • anonymous
can someone just help me? lol. i'm kinda stuck on this question >_<
Hero
  • Hero
2r^2-11r+5=0 2r^2-10r-1r+5 = 0 2r(r-5)-1(r-5) = 0 (r-5)(2r-1) = 0 r = 1/2 r = 5
anonymous
  • anonymous
Hero is right.
Mimi_x3
  • Mimi_x3
You can also use the quadratic formula, which is faster i guess. \[\large x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]
Hero
  • Hero
Nope, I'm faster. The quad formula is whack.
anonymous
  • anonymous
Hahaha!
Hero
  • Hero
Mimi uses it because she can't factor :P
Mimi_x3
  • Mimi_x3
Nope, well..the using the quadratic you won't need to think much as to factor where you mgiht make stupid mistakes.
Hero
  • Hero
Mimi, you forgot to put the line that protects your discriminant :P
Mimi_x3
  • Mimi_x3
what line?
Hero
  • Hero
The square root line.....(DUH) :P
Mimi_x3
  • Mimi_x3
wtf..there's nothing wrong :/ You're confusing me :/
Hero
  • Hero
lol, just teasing. Don't cry on me :P
anonymous
  • anonymous
HERO. one last question. i beg.
Mimi_x3
  • Mimi_x3
Oh..gawd, confusing a poor kid that just woke up :'(
Hero
  • Hero
Here we go again with the "poor little kid" retreat line you always pull :P
Mimi_x3
  • Mimi_x3
You dont have the right to alternate my phrases i said "poor kid" NOT "poor little kid" :P
Hero
  • Hero
poor kid = poor little kid To me it's the exact same thing. A sympathy plea
anonymous
  • anonymous
kwell, I'm just gonna ask. 2c^2+c-10=0
Hero
  • Hero
Mimi can use her quad form to help you
Mimi_x3
  • Mimi_x3
Excuse me, its not a "sympathy plea" i never told you to be pity me. GOsh people these days who dont have common sense.
anonymous
  • anonymous
i don't remember crap about the quad form hah.
Mimi_x3
  • Mimi_x3
Because Hero is unable to factor it :P
Mimi_x3
  • Mimi_x3
\[\large c=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \] \[\large c=\frac{-(1)\pm\sqrt{(1)^{2}-4(2)(-10)}}{2(2)} \]
Hero
  • Hero
2c^2+c-10=0 2c^2+5c-4c-10 = 0 c(2c+5)-2(2c+5) = 0 (2c+5)(c-2) = 0 c = -5/2, 2
Hero
  • Hero
Mimi jinxed me.
Mimi_x3
  • Mimi_x3
lol, i told you that you will make stupid mistakes :P The factor method is such a FAIL!
anonymous
  • anonymous
Mimi made careless mistakes! :O
Hero
  • Hero
Quad Form is an even bigger fail, especially when you depend on it so much Mimi :P
Hero
  • Hero
I know about 5 different factor methods
Hero
  • Hero
None of which include the dreaded quad form
anonymous
  • anonymous
how would you use the quad form on questions like 25m^2-64=0??
Mimi_x3
  • Mimi_x3
What? You dont have the right to say that its a fail since i got it right in the first go, not like you who go it WRONG! EVen during exams it would be a waste of time to do it again :P
anonymous
  • anonymous
a.k.a binomials.
Hero
  • Hero
25m^2 - 64 = 0 25m^2 = 64 m^2 = 64/25 m = sqrt{64/25} m = plus or minus 8/5
Mimi_x3
  • Mimi_x3
Btw, quadratic formula can only be used for ax^3+bx+c
anonymous
  • anonymous
Oh right, I totally knew that.
Mimi_x3
  • Mimi_x3
ax^2*
Hero
  • Hero
Yeah, the quad form is LIMITED
Hero
  • Hero
While I was working hard to provide your solution sakigirl. Mimi, started making useless comments
anonymous
  • anonymous
hahah, forgetting the line of the square root. Oh silly her.
Mimi_x3
  • Mimi_x3
I was trying to help her know a better method to solve it which is quicker. I was being nice
Hero
  • Hero
I was being nicer :P
Mimi_x3
  • Mimi_x3
whaat? forgettng the line of the square root?
Hero
  • Hero
lol
anonymous
  • anonymous
Yeah! and Hero commented on it
Hero
  • Hero
lol
Mimi_x3
  • Mimi_x3
lol, sorry to say i think you should scroll up, i never make those carelless mistakes.
Hero
  • Hero
you just made one, then auto corrected it. Putting ax^3 , then ax^2. Such silly mistakes :P
Mimi_x3
  • Mimi_x3
its called a TYPO, you make stupid mistakes as well argh..i should never comment in questions that you are in anymore.

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