Solve: 2r^2-11x+5=0 Thanks :) p.s. explain?

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Solve: 2r^2-11x+5=0 Thanks :) p.s. explain?

Mathematics
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Do you know the quadratic formula?
The variables should be the same, right?
Agreed.

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Other answers:

Good eye.
Good eye? It was blatantly obvious, lol :P
oh right! My teacher made a typo, lol. they should both be r's. and no, I don't remember anything from algebra 1! Which is bad :/
How do you know they shouldn't both be x's?
well, letters don't really matter. whichever you replace, they would still be the same problem. just different letters.
I think he's being humorous, sakigirl.
can someone just help me? lol. i'm kinda stuck on this question >_<
2r^2-11r+5=0 2r^2-10r-1r+5 = 0 2r(r-5)-1(r-5) = 0 (r-5)(2r-1) = 0 r = 1/2 r = 5
Hero is right.
You can also use the quadratic formula, which is faster i guess. \[\large x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]
Nope, I'm faster. The quad formula is whack.
Hahaha!
Mimi uses it because she can't factor :P
Nope, well..the using the quadratic you won't need to think much as to factor where you mgiht make stupid mistakes.
Mimi, you forgot to put the line that protects your discriminant :P
what line?
The square root line.....(DUH) :P
wtf..there's nothing wrong :/ You're confusing me :/
lol, just teasing. Don't cry on me :P
HERO. one last question. i beg.
Oh..gawd, confusing a poor kid that just woke up :'(
Here we go again with the "poor little kid" retreat line you always pull :P
You dont have the right to alternate my phrases i said "poor kid" NOT "poor little kid" :P
poor kid = poor little kid To me it's the exact same thing. A sympathy plea
kwell, I'm just gonna ask. 2c^2+c-10=0
Mimi can use her quad form to help you
Excuse me, its not a "sympathy plea" i never told you to be pity me. GOsh people these days who dont have common sense.
i don't remember crap about the quad form hah.
Because Hero is unable to factor it :P
\[\large c=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \] \[\large c=\frac{-(1)\pm\sqrt{(1)^{2}-4(2)(-10)}}{2(2)} \]
2c^2+c-10=0 2c^2+5c-4c-10 = 0 c(2c+5)-2(2c+5) = 0 (2c+5)(c-2) = 0 c = -5/2, 2
Mimi jinxed me.
lol, i told you that you will make stupid mistakes :P The factor method is such a FAIL!
Mimi made careless mistakes! :O
Quad Form is an even bigger fail, especially when you depend on it so much Mimi :P
I know about 5 different factor methods
None of which include the dreaded quad form
how would you use the quad form on questions like 25m^2-64=0??
What? You dont have the right to say that its a fail since i got it right in the first go, not like you who go it WRONG! EVen during exams it would be a waste of time to do it again :P
a.k.a binomials.
25m^2 - 64 = 0 25m^2 = 64 m^2 = 64/25 m = sqrt{64/25} m = plus or minus 8/5
Btw, quadratic formula can only be used for ax^3+bx+c
Oh right, I totally knew that.
ax^2*
Yeah, the quad form is LIMITED
While I was working hard to provide your solution sakigirl. Mimi, started making useless comments
hahah, forgetting the line of the square root. Oh silly her.
I was trying to help her know a better method to solve it which is quicker. I was being nice
I was being nicer :P
whaat? forgettng the line of the square root?
lol
Yeah! and Hero commented on it
lol
lol, sorry to say i think you should scroll up, i never make those carelless mistakes.
you just made one, then auto corrected it. Putting ax^3 , then ax^2. Such silly mistakes :P
its called a TYPO, you make stupid mistakes as well argh..i should never comment in questions that you are in anymore.

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