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anonymous
 5 years ago
trying to find the second derivative in this question......3x3 over 2x+4. the Vertical Asy is 2 and the Horizontal Asy is 3/2...the xint is (1,0) and the yint is (0,3/4) please give me step buy step
anonymous
 5 years ago
trying to find the second derivative in this question......3x3 over 2x+4. the Vertical Asy is 2 and the Horizontal Asy is 3/2...the xint is (1,0) and the yint is (0,3/4) please give me step buy step

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you find the first derivative? because that is the only hard part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0quotient rule give \[\frac{d}{dx}\frac{3x3}{2x+4}=\frac{(2x+4)\times 3(3x+3)\times 2}{(2x+4)^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i have the first one all ready

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you end up with \[\frac{9}{(2x+4)^2}=9(2x+4)^{2}\] now second should be easy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[18(2x+4)^{3}\times 2=36(2x+4)^{3}=\frac{36}{(2x+4)^3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can cancel a little because \[(2x+4)^3=(2(x+2))^3=8(x+2)^3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok which step? did you get the first derivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got (2x+4)2(3x3) over (2x+4)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you have to do the algebra in the numerator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0should be \[(2x+4)32(3x3) \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in front of the 2x+4 there is suppose to be a 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it is the denominator times the derivative of the numerator as the first term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0minus the numerator times the derivative of the denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you multiply out the x terms add up to zero and you get 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 18 over (2x+4)^2 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(2x+4)32(3x3)\] \[6x+126x+6=18\] yes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my equation is 3(2x+4)2(3x3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes multiply out and you will get 18

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok then what do i do to get the second answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have \[\frac{18}{(2x+4)^2}\] so rather than using the quotient rule again, rewrite in exponential form as \[18\times (2x+4)^{2}\] and use the power rule (and the chain rule)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so multiple it out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0power rule right? \[\frac{d}{dx}x^n=nx^{n1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i made a mistake, sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}18(2x+4)^{2}=2\times 18(2x+4)^{21}\times 2\] \[=72(2x+4)^{3}=\frac{72}{(2x+4)^3}\] but you can simplify this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because \[(2x+4)^3=(2(x+2))^3=8(x+2)^3\] and \[\frac{72}{8}=9\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so your "final answer" will be \[\frac{9}{(x+2)^3}\]
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