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anonymous
 4 years ago
Find a number k such that the given equation has exactly one real solution.
x^2kx+4=0
anonymous
 4 years ago
Find a number k such that the given equation has exactly one real solution. x^2kx+4=0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer is 4 or 4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you just use the discriminant

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0use b^2  4ac = 0 from the GQF..... or (k)^2  4x1x4 = 0 and solve

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0ax^2+bx+c=0 for one real solution D=b^24ac=0 here a=1 b=k c=4 K^24*1*4=0 k^216=0 so \(k=\pm 4\)
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