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anonymous
 4 years ago
find the region of the solid formed by rotating the area bounded by y=3, y=sqrt(x), and the xaxis. Rotate around x=10.
anonymous
 4 years ago
find the region of the solid formed by rotating the area bounded by y=3, y=sqrt(x), and the xaxis. Rotate around x=10.

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ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0we have the curve y=sqrt (x)dw:1327469538153:dw

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0if we have to calculate area bounded, it'll be between the curves x=y^2 and x=10 take a rectangle of length 10y^2 and thickness dy, y will vary from y=3 to y= root 10 \[\int\limits_{3}^{\sqrt{10}}( 10y^2) dy\] now the area is rotated about x=10 so the volume of a disc= \(\pi*(10y^2)*dy\) radius is 10y^2 thickness is dy y will vary from y=3 to y= \(\sqrt 10\) Volume =\(\int\limits_{3}^{\sqrt{10}} \pi* (10y^2)^2dy\) solving the integral, you'll get volume =0.1712 http://www.wolframalpha.com/input/?i=integrate+%28pi*%2810y%5E2%29%5E2%29dy+from+y%3D3+to+y%3D+10%5E%281%2F2%29
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